Pertanyaan

Dari hasil percobaan reaksi: A + 2 B + 3 C → produk diperoleh data sebagai berikut: Tentukan persamaan laju reaksinya dan orde reaksi totalnya!

Dari hasil percobaan reaksi: $A + 2 B + 3 C \to produk$
diperoleh data sebagai berikut:

Tentukan persamaan laju reaksinya dan orde reaksi totalnya! $\;$

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Master Teacher

Jawaban terverifikasi

Jawaban

maka persamaan laju reaksinya adalah: , sedangkan orde reaksi totalnya adalah: x+y+z = 3.

maka persamaan laju reaksinya adalah: V double bond k open square brackets A close square brackets open square brackets B close square brackets open square brackets C close square brackets

V double bond k open square brackets A close square brackets open square brackets B close square brackets open square brackets C close square brackets

, sedangkan orde reaksi totalnya adalah: x+y+z = 3. space

Pembahasan

Pertama menentukan orde reaksi A dengan perbandingan data 2 banding 1 yaitu: Orde reaksi B dengan perbandingan data 3 dan 2 yaitu: Orde C dengan perbandingan data 3 dan 4 yaitu: Dengan demikian maka persamaan laju reaksinya adalah: , sedangkan orde reaksi totalnya adalah: x+y+z = 3.

Pertama menentukan orde reaksi A dengan perbandingan data 2 banding 1 yaitu:

$table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets A close square brackets to the power of italic x open square brackets B close square brackets to the power of italic y open square brackets C close square brackets to the power of italic z end cell equals V row cell open square brackets fraction numerator 6 cross times 10 to the power of negative sign 2 end exponent over denominator 3 cross times 10 to the power of negative sign 2 end exponent end fraction close square brackets to the power of x open square brackets fraction numerator 1 comma 7 cross times 10 to the power of negative sign 2 end exponent over denominator 1 comma 7 cross times 10 to the power of negative sign 2 end exponent end fraction close square brackets to the power of y open square brackets 10 to the power of negative sign 7 end exponent over 10 to the power of negative sign 7 end exponent close square brackets to the power of z end cell equals cell fraction numerator 10 cross times 10 to the power of negative sign 5 end exponent over denominator 5 cross times 10 to the power of negative sign 5 end exponent end fraction end cell row cell open square brackets 6 over 3 close square brackets to the power of x end cell equals cell 10 over 5 end cell row cell open square brackets 2 close square brackets to the power of x end cell equals cell 2 to the power of 1 end cell row x equals 1 end table$

Orde reaksi B dengan perbandingan data 3 dan 2 yaitu:

$table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets A close square brackets to the power of italic x open square brackets B close square brackets to the power of italic y open square brackets C close square brackets to the power of italic z end cell equals V row cell open square brackets fraction numerator 3 cross times 10 to the power of negative sign 2 end exponent over denominator 6 cross times 10 to the power of negative sign 2 end exponent end fraction close square brackets to the power of x open square brackets fraction numerator 3 comma 4 cross times 10 to the power of negative sign 2 end exponent over denominator 1 comma 7 cross times 10 to the power of negative sign 2 end exponent end fraction close square brackets to the power of y open square brackets 10 to the power of negative sign 7 end exponent over 10 to the power of negative sign 7 end exponent close square brackets to the power of z end cell equals cell fraction numerator 10 cross times 10 to the power of negative sign 5 end exponent over denominator 10 cross times 10 to the power of negative sign 5 end exponent end fraction end cell row cell open square brackets 1 half close square brackets to the power of 1 open square brackets 2 close square brackets to the power of y end cell equals 1 row cell open square brackets 2 close square brackets to the power of italic y end cell equals cell 2 to the power of 1 end cell row y equals 1 end table$

Orde C dengan perbandingan data 3 dan 4 yaitu:

$table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets A close square brackets to the power of italic x open square brackets B close square brackets to the power of italic y open square brackets C close square brackets to the power of italic z end cell equals V row cell open square brackets fraction numerator 3 cross times 10 to the power of negative sign 2 end exponent over denominator 3 cross times 10 to the power of negative sign 2 end exponent end fraction close square brackets to the power of x open square brackets fraction numerator 1 comma 7 cross times 10 to the power of negative sign 2 end exponent over denominator 3 comma 4 cross times 10 to the power of negative sign 2 end exponent end fraction close square brackets to the power of y open square brackets fraction numerator 2 cross times 10 to the power of negative sign 7 end exponent over denominator 10 to the power of negative sign 7 end exponent end fraction close square brackets to the power of z end cell equals cell fraction numerator 10 cross times 10 to the power of negative sign 5 end exponent over denominator 10 cross times 10 to the power of negative sign 5 end exponent end fraction end cell row cell open square brackets 1 half close square brackets to the power of 1 open square brackets 2 close square brackets to the power of italic z end cell equals 1 row cell open square brackets 2 close square brackets to the power of italic z end cell equals cell 2 to the power of 1 end cell row z equals 1 end table$

Dengan demikian maka persamaan laju reaksinya adalah: V double bond k open square brackets A close square brackets open square brackets B close square brackets open square brackets C close square brackets , sedangkan orde reaksi totalnya adalah: x+y+z = 3. space

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