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Pada percobaan reaksi P+2Q→PQ2​ diperoleh data-data percobaan sebagai berikut. Tentukan : a.  orde reaksi terhadap P  b.  orde reaksi terhadap Q  c.  orde reaksi total d.  harga tetapan k  e.  persamaan laju reaksi f.  besarnya x

Pertanyaan

Pada percobaan reaksi begin mathsize 14px style P and 2 Q yields PQ subscript 2 end style diperoleh data-data percobaan sebagai berikut.



Tentukan :

a.  orde reaksi terhadap begin mathsize 14px style P end style 

b.  orde reaksi terhadap begin mathsize 14px style Q end style 

c.  orde reaksi total

d.  harga tetapan begin mathsize 14px style k end style 

e.  persamaan laju reaksi

f.  besarnya begin mathsize 14px style x end style 

Pembahasan Video:

Pembahasan:

a) Orde reaksi P

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 over t subscript 1 over denominator 1 over t subscript 2 end fraction end cell equals cell fraction numerator italic k open square brackets P close square brackets to the power of x open square brackets Q close square brackets to the power of y over denominator italic k open square brackets P close square brackets to the power of x open square brackets Q close square brackets to the power of y end fraction end cell row cell fraction numerator 1 over 128 over denominator 1 over 64 end fraction end cell equals cell fraction numerator italic k left square bracket 0 comma 1 right square bracket to the power of italic x left square bracket 0 comma 1 right square bracket to the power of italic y over denominator italic k left square bracket 0 comma 2 right square bracket to the power of x left square bracket 0 comma 1 right square bracket to the power of y end fraction space space space space left parenthesis italic k italic i italic t italic a space italic e italic l italic i italic m italic i italic n italic a italic s italic i space italic k space italic d italic a italic n space left square bracket 0 comma 1 right square bracket to the power of italic y right parenthesis space space end cell row cell 64 over 128 end cell equals cell left square bracket 0 comma 1 right square bracket to the power of italic x over left square bracket 0 comma 2 right square bracket to the power of italic x end cell row cell 1 half end cell equals cell left square bracket 0 comma 1 right square bracket to the power of italic x over left square bracket 0 comma 2 right square bracket to the power of italic x end cell row italic x equals 1 end table end style  

Jadi, orde reaksi P adalah 1.

b) Orde reaksi Q
begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 over t subscript 1 over denominator 1 over t subscript 3 end fraction end cell equals cell fraction numerator italic k open square brackets P close square brackets to the power of x open square brackets Q close square brackets to the power of y over denominator italic k open square brackets P close square brackets to the power of x open square brackets Q close square brackets to the power of y end fraction end cell row cell fraction numerator 1 over 128 over denominator 1 over 32 end fraction end cell equals cell fraction numerator italic k left square bracket 0 comma 1 right square bracket to the power of italic x left square bracket 0 comma 1 right square bracket to the power of italic y over denominator italic k left square bracket 0 comma 1 right square bracket to the power of x left square bracket left square bracket 0 comma 2 right square bracket to the power of y end fraction space space space space space space left parenthesis italic k italic i italic t italic a space italic e italic l italic i italic m italic i italic n italic a italic s italic i space italic k space italic d italic a italic n space left square bracket 0 comma 1 right square bracket to the power of italic x right parenthesis space end cell row cell 32 over 128 end cell equals cell left square bracket 0 comma 1 right square bracket to the power of italic y over left square bracket 0 comma 2 right square bracket to the power of italic y end cell row cell 1 fourth end cell equals cell left square bracket 0 comma 1 right square bracket to the power of italic y over left square bracket 0 comma 2 right square bracket to the power of italic y end cell row italic y equals 2 end table end style

Jadi, orde reaksi Q adalah 2.

c)  Orde reaksi total

Orde reaksi total = orde P + orde Q = 1 + 2 = 3

d)  Harga tetapan k

Substitusikan hasil orde reaksi kedalam persamaan berikut :

begin mathsize 14px style v double bond k open square brackets P close square brackets to the power of 1 open square brackets Q close square brackets squared 1 over t equals k open square brackets P close square brackets to the power of 1 open square brackets Q close square brackets squared end style   

Sebagai contoh percobaan pertama
table attributes columnalign right center left columnspacing 0px end attributes row cell 1 over 128 end cell equals cell italic k left square bracket 0 comma 1 right square bracket to the power of 1 left square bracket 0 comma 1 right square bracket squared space end cell row cell 1 over 128 end cell equals cell k cross times 0 comma 1 cross times 0 comma 01 end cell row k equals cell fraction numerator 1 over denominator 128 cross times 0 comma 1 cross times 0 comma 01 end fraction end cell row k equals cell 7 comma 81 space M cubed space s to the power of negative sign 1 end exponent end cell end table

Jadi, nilai tetapan lajunya (k) adalah 7,81.

e)  Persamaan laju reaksi

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row v equals cell 7 comma 81 open square brackets P close square brackets to the power of 1 open square brackets Q close square brackets squared space end cell end table end style

f)  Besarnya nilai x

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row v equals cell 7 comma 81 left square bracket 0 comma 2 right square bracket left square bracket 0 comma 4 right square bracket squared space end cell row cell 1 over x end cell equals cell 7 comma 81 cross times 0 comma 2 cross times 0 comma 16 end cell row x equals cell fraction numerator 1 over denominator 7 comma 81 cross times 0 comma 2 cross times 0 comma 16 end fraction end cell row x equals 4 end table end style 

Jadi, nilai x adalah 4 detik

Jawaban terverifikasi

Dijawab oleh:

N. Puspita

Terakhir diupdate 07 Oktober 2021

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