Tentukan orde reaksi total, harga k, persamaan laju reaksi, dan grafik orde reaksi dari data percobaan pada soal berikut! Reaksi: I−(aq)+ClO−(aq)→IO−(g)+Cl−(l)

Pertanyaan

Tentukan orde reaksi total, harga k, persamaan laju reaksi, dan grafik orde reaksi dari data percobaan pada soal berikut!

Reaksi: I to the power of minus sign left parenthesis italic a italic q right parenthesis plus Cl O to the power of minus sign left parenthesis italic a italic q right parenthesis yields I O to the power of minus sign open parentheses italic g close parentheses and Cl to the power of minus sign open parentheses italic l close parentheses
 

B. Rohmawati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

jawaban sesuai dengan uraian di atas.

Pembahasan

Persamaan laju reaksi secara umum :

V double bond k space open square brackets I to the power of minus sign close square brackets to the power of x open square brackets Cl O to the power of minus sign close square brackets to the power of y

Orde reaksi terhadap I to the power of minus sign (data 1 dan 2)

Error converting from MathML to accessible text.

 

Orde reaksi terhadap Cl O to the power of minus sign (data 1 dan 3)

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript 3 over V subscript 1 end cell equals cell fraction numerator k space open square brackets I to the power of minus sign close square brackets to the power of x open square brackets Cl O to the power of minus sign close square brackets to the power of y over denominator k space open square brackets I to the power of minus sign close square brackets to the power of x open square brackets Cl O to the power of minus sign close square brackets to the power of y end fraction end cell row cell fraction numerator 2 comma 72 space x 10 to the power of negative sign 4 end exponent over denominator 1 comma 36 space x 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator up diagonal strike k space up diagonal strike left square bracket 1 comma 5 x 10 to the power of negative sign 3 end exponent right square bracket to the power of x space end strike space open square brackets 3 comma 0 space x 10 to the power of negative sign 3 end exponent close square brackets to the power of y over denominator up diagonal strike k space up diagonal strike left square bracket 1 comma 5 space x 10 to the power of negative sign 3 end exponent right square bracket to the power of x end strike space open square brackets 1 comma 5 space x 10 to the power of negative sign 3 end exponent close square brackets to the power of y end fraction end cell row cell 2 to the power of 1 end cell equals cell 2 to the power of y end cell row y equals 1 end table

Kedua zat memiliki orde 1 maka grafik dari orde satu dapat digambarkan sebagai berikut:

Orde reaksi total = x + y = 1+1 = 2

Persamaan laju reaksi menjadi V double bond k space open square brackets I to the power of minus sign close square brackets open square brackets Cl O to the power of minus sign close square brackets

Penentuan harga k (misal ambil data no 1)

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript 1 end cell equals cell k space open square brackets I to the power of minus sign close square brackets open square brackets Cl O to the power of minus sign close square brackets end cell row cell 1 comma 36 space x 10 to the power of negative sign 4 end exponent end cell equals cell k space left square bracket 1 comma 5 x 10 to the power of negative sign 3 end exponent right square bracket left square bracket 1 comma 5 x 10 to the power of negative sign 3 end exponent right square bracket end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row k equals cell fraction numerator 1 comma 36 x 10 to the power of negative sign 4 end exponent space M space detik to the power of negative sign 1 end exponent over denominator open parentheses 1 comma 5 x 10 to the power of negative sign 3 end exponent space M close parentheses squared end fraction end cell row blank equals cell fraction numerator 1 comma 36 x 10 to the power of negative sign 4 end exponent space M space detik to the power of negative sign 1 end exponent over denominator 2 comma 25 x 10 to the power of negative sign 6 end exponent space M squared end fraction end cell row blank equals cell 60 comma 44 space M to the power of negative sign 1 end exponent space M to the power of negative sign 1 end exponent space detik to the power of negative sign 1 end exponent end cell end table

Jadi, jawaban sesuai dengan uraian di atas.

637

5.0 (2 rating)

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