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dan , maka nilai − det A = … + 3 m u .

begin mathsize 14px style A equals open square brackets table row a b row c 0 end table close square brackets end style dan begin mathsize 14px style A squared equals open square brackets table row 20 8 row d 4 end table close square brackets end style, maka nilai   

  1. 4

  2. -4

  3. 8

  4. -8

  5. 20

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A. C

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Sehingga Didapatkan Dengan bc = 4 didapatkan Maka

begin mathsize 14px style A equals open square brackets table row a b row c 0 end table close square brackets end style 

Sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell A squared end cell equals cell open square brackets table row 20 8 row d 4 end table close square brackets end cell row cell open square brackets table row a b row c 0 end table close square brackets open square brackets table row a b row c 0 end table close square brackets end cell equals cell open square brackets table row 20 8 row d 4 end table close square brackets end cell row cell open square brackets table row cell a squared plus b c end cell cell a b end cell row cell a c end cell cell b c end cell end table close square brackets end cell equals cell open square brackets table row 20 8 row d 4 end table close square brackets end cell end table end style  


Didapatkan 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell a squared plus b c end cell equals 20 row cell a b end cell equals 8 row cell a c end cell equals d row cell b c end cell equals 4 end table end style  


Dengan bc = 4 didapatkan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell negative det invisible function application A end cell equals cell negative open parentheses negative b c close parentheses end cell row blank equals cell negative open parentheses negative 4 close parentheses end cell row blank equals 4 end table end style  


Maka begin mathsize 14px style negative det invisible function application A equals 4 end style  

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M = [ a c ​ b 0 ​ ] dan M ⋅ [ a c ​ b 0 ​ ] = [ 190 d ​ 20 90 ​ ] , maka nilai det A 900 ​ = ...

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