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Dalam sebuah kotak terdapat 5 bola hijau dan 4 bola kuning. Bila diambil 2 bola sekaligus, peluang terambilnya 1 bola hijau dan 1 bola kuning adalah.....

Dalam sebuah kotak terdapat 5 bola hijau dan 4 bola kuning. Bila diambil 2 bola sekaligus, peluang terambilnya 1 bola hijau dan 1 bola kuning adalah.....

  1. 2 over 81

  2. 2 over 9

  3. 4 over 9

  4. 5 over 9

  5. 20 over 81

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K a r e n a space y a n g space d i tan y a space b e r a p a space p e l u a n g space t e r a m b i ln y a space 1 space b o l a space h i j a u space bold italic d bold italic a bold italic n  1 space b o l a space k u n i n g comma space m a k a space p e l u a n g space t e a m b i ln y a space 1 space b o l a space m e r a h space bold italic d bold italic i bold italic k bold italic a bold italic l bold italic i space 1 space b o l a space k u n i n g comma space y a i t u  P left parenthesis A right parenthesis equals fraction numerator n left parenthesis A right parenthesis over denominator n left parenthesis S right parenthesis end fraction  equals fraction numerator C presubscript 5 subscript 1 space cross times space C presubscript 4 subscript 1 over denominator C presubscript 9 subscript 2 end fraction  equals fraction numerator begin display style fraction numerator 5 factorial over denominator 1 factorial left parenthesis 5 minus 1 right parenthesis factorial end fraction end style cross times begin display style fraction numerator 4 factorial over denominator 1 factorial left parenthesis 4 minus 1 right parenthesis factorial end fraction end style over denominator begin display style fraction numerator 9 factorial over denominator 2 factorial open parentheses 9 minus 2 close parentheses factorial end fraction end style end fraction  equals fraction numerator 5 cross times 4 over denominator begin display style fraction numerator 9 cross times 8 cross times 7 factorial over denominator 2 factorial cross times 7 factorial end fraction end style end fraction  equals 20 over 36  equals 5 over 9K a r e n a space y a n g space d i tan y a space b e r a p a space p e l u a n g space t e r a m b i ln y a space 1 space b o l a space h i j a u space bold italic d bold italic a bold italic n  1 space b o l a space k u n i n g comma space m a k a space p e l u a n g space t e a m b i ln y a space 1 space b o l a space m e r a h space bold italic d bold italic i bold italic k bold italic a bold italic l bold italic i space 1 space b o l a space k u n i n g comma space y a i t u  P left parenthesis A right parenthesis equals fraction numerator n left parenthesis A right parenthesis over denominator n left parenthesis S right parenthesis end fraction  equals fraction numerator C presubscript 5 subscript 1 space cross times space C presubscript 4 subscript 1 over denominator C presubscript 9 subscript 2 end fraction  equals fraction numerator begin display style fraction numerator 5 factorial over denominator 1 factorial left parenthesis 5 minus 1 right parenthesis factorial end fraction end style cross times begin display style fraction numerator 4 factorial over denominator 1 factorial left parenthesis 4 minus 1 right parenthesis factorial end fraction end style over denominator begin display style fraction numerator 9 factorial over denominator 2 factorial open parentheses 9 minus 2 close parentheses factorial end fraction end style end fraction  equals fraction numerator 5 cross times 4 over denominator begin display style fraction numerator 9 cross times 8 cross times 7 factorial over denominator 2 factorial cross times 7 factorial end fraction end style end fraction  equals 20 over 36  equals 5 over 9

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Dalam suatu kotak terdapat 4 bola merah, 5 bola biru, dan 3 bola hijau. Jika dari kotak tersebut diambil dua bola sekaligus secara acak, peluang terambil dua bola biru atau dua bola hijau adalah ...

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