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Buktikan bahwa: k = 10 ∑ ​ 20 ​ ( k 2 + 20 k + 103 ) + k = 10 ∑ ​ n − 11 ​ ( k 2 + 42 k + 444 ) = k = 20 ∑ ​ n + 10 ​ ( k 2 + 3 )

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E. Dwi

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

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begin mathsize 14px style sum from k equals 10 to 20 of left parenthesis k squared plus 20 k plus 103 right parenthesis plus sum from k equals 10 to n minus 11 of left parenthesis k squared plus 42 k plus 444 right parenthesis equals sum from k equals 10 plus 10 to 20 plus 10 of left parenthesis left parenthesis k minus 10 right parenthesis squared plus 20 left parenthesis k minus 10 right parenthesis plus 103 right parenthesis space space space space space space plus sum from k equals 10 plus 21 to n minus 11 plus 21 of left parenthesis left parenthesis k minus 21 right parenthesis squared plus 42 left parenthesis k minus 21 right parenthesis plus 444 right parenthesis equals sum from k equals 20 to 30 of left parenthesis k squared minus 20 k plus 100 plus 20 k minus 200 plus 103 right parenthesis space space space space space space plus sum from k equals 31 to n plus 10 of left parenthesis k squared minus 42 k plus 441 plus 42 k minus 882 plus 444 right parenthesis equals sum from k equals 20 to 30 of left parenthesis k squared plus 3 right parenthesis plus sum from k equals 31 to n plus 10 of left parenthesis k squared plus 3 right parenthesis equals sum from k equals 20 to n plus 10 of left parenthesis k squared plus 3 right parenthesis subscript left parenthesis Terbukti right parenthesis end subscript end style   

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