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Buktikan bahwa: k = 1 ∑ n ​ k 2 + k = 4 ∑ n + 3 ​ ( 2 k + 1 ) = k = 1 ∑ n ​ ( k 2 + 2 k + 7 )

Buktikan bahwa:

 

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E. Dwi

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

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Pembahasan

begin mathsize 14px style sum from k plus 1 to n of k squared plus sum from k equals 4 to n plus 3 of left parenthesis 2 k plus 1 right parenthesis equals sum from k plus 1 to n of k squared plus sum from k equals 4 minus 3 to n plus 3 minus 3 of left parenthesis 2 left parenthesis k plus 3 right parenthesis plus 1 right parenthesis equals sum from k plus 1 to n of k squared plus sum from k equals 1 to n of left parenthesis 2 k plus 6 plus 1 right parenthesis equals sum from k plus 1 to n of k squared plus sum from k equals 1 to n of left parenthesis 2 k plus 7 right parenthesis equals sum from k plus 1 to n of left parenthesis k squared plus 2 k plus 7 right parenthesis subscript left parenthesis Terbukti right parenthesis end subscript space end style 

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