Roboguru

Bentuk untuk dapat dinyatakan sebagai...

Bentuk square root of 3 space cos space x space minus space sin space x untuk 0 less or equal than x less or equal than 2 straight pi dapat dinyatakan sebagai...

  1. 2 space cos space open parentheses x plus straight pi over 6 close parentheses

  2. 2 space cos space open parentheses x plus fraction numerator 7 straight pi over denominator 6 end fraction close parentheses

  3. 2 space cos space open parentheses x plus fraction numerator 11 straight pi over denominator 6 end fraction close parentheses

  4. 2 space cos space open parentheses x minus fraction numerator 7 straight pi over denominator 6 end fraction close parentheses

  5. 2 space cos space open parentheses x minus straight pi over 6 close parentheses

Jawaban:

square root of 3 cos space x minus sin space x equals space k space cos space left parenthesis x minus alpha right parenthesis  k equals square root of open parentheses square root of 3 close parentheses squared plus open parentheses negative 1 close parentheses squared end root equals square root of 3 plus 1 end root equals square root of 4 equals 2  tan space alpha equals b over a equals negative fraction numerator 1 over denominator square root of 3 end fraction  alpha equals negative straight pi over 6  square root of 3 cos minus sin space x equals 2 space cos space open parentheses x plus straight pi over 6 close parentheses

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