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Bentuk sederhana dari ( 9 p 2 q − 3 ) 4 ⋅ ( 27 p 4 q − 2 ) − 3 = ....

Bentuk sederhana dari

 

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N. Puspita

Master Teacher

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hasil dari yang tepat adalah .

hasil dari open parentheses 9 straight p squared straight q to the power of negative 3 end exponent close parentheses to the power of 4 times open parentheses 27 straight p to the power of 4 straight q to the power of negative 2 end exponent close parentheses to the power of negative 3 end exponent yang tepat adalah fraction numerator 1 over denominator 3 straight p to the power of 4 straight q to the power of 6 end fraction.

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Ingat kembali aturan perkalian bilangan berpangkat yaitu Sehingga: Jadi, hasil dari yang tepat adalah .

Ingat kembali aturan perkalian bilangan berpangkat yaitu

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell straight a to the power of straight m cross times straight a to the power of straight n equals straight a to the power of straight m plus straight n end exponent end cell end table

Sehingga:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 9 straight p squared straight q to the power of negative 3 end exponent close parentheses to the power of 4 times open parentheses 27 straight p to the power of 4 straight q to the power of negative 2 end exponent close parentheses to the power of negative 3 end exponent end cell equals cell 3 to the power of 8 straight p to the power of 8 straight q to the power of negative 12 end exponent 3 to the power of negative 9 end exponent straight p to the power of negative 12 end exponent straight q to the power of 6 end cell row blank equals cell 3 to the power of 8 minus 9 end exponent straight p to the power of 8 minus 12 end exponent straight q to the power of negative 12 plus 6 end exponent end cell row blank equals cell 3 to the power of negative 1 end exponent straight p to the power of negative 4 end exponent straight q to the power of negative 6 end exponent end cell row blank equals cell fraction numerator 1 over denominator 3 straight p to the power of 4 straight q to the power of 6 end fraction end cell end table

Jadi, hasil dari open parentheses 9 straight p squared straight q to the power of negative 3 end exponent close parentheses to the power of 4 times open parentheses 27 straight p to the power of 4 straight q to the power of negative 2 end exponent close parentheses to the power of negative 3 end exponent yang tepat adalah fraction numerator 1 over denominator 3 straight p to the power of 4 straight q to the power of 6 end fraction.

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