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Pertanyaan

Bentuk sederhana dari ( 24 a 5 b − 3 c 3 a − 2 bc − 3 ​ ) − 1 adalah ....

Bentuk sederhana dari  adalah ....

  1. fraction numerator 8 straight a to the power of 7 straight c to the power of 4 over denominator straight b to the power of 4 end fraction 

  2. fraction numerator 8 straight a to the power of 10 straight c cubed over denominator straight b to the power of 4 end fraction 

  3. fraction numerator 8 straight a to the power of 7 straight c cubed over denominator straight b cubed end fraction 

  4. fraction numerator 8 straight a to the power of 10 straight b cubed over denominator straight c cubed end fraction 

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N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

jawaban yang benar adalah A.

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Pembahasan

Pembahasan
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Diketahui suatu bentuk eksponen . Berdasarkan sifat bilangan berpangkat negatif yaitu maka Berdasarkan sifat bilangan berpangkat pembagian yaitu sehingga diperoleh Oleh karena itu, jawaban yang benar adalah A.

Diketahui suatu bentuk eksponen open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses to the power of negative 1 end exponent. Berdasarkan sifat bilangan berpangkat negatif yaitu a to the power of negative n end exponent equals 1 over a to the power of n maka

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses to the power of negative 1 end exponent end cell equals cell fraction numerator 1 over denominator open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses end fraction end cell row cell open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses to the power of negative 1 end exponent end cell equals cell fraction numerator 1 over denominator fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction end fraction end cell row cell open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses to the power of negative 1 end exponent end cell equals cell fraction numerator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c over denominator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent end fraction end cell end table

Berdasarkan sifat bilangan berpangkat pembagian yaitu a to the power of m over a to the power of n equals a to the power of m minus n end exponent sehingga diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses to the power of negative 1 end exponent end cell equals cell fraction numerator begin display style stack up diagonal strike 24 with 8 on top end style straight a to the power of 5 straight b to the power of negative 3 end exponent straight c over denominator up diagonal strike 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent end fraction end cell row cell open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses to the power of negative 1 end exponent end cell equals cell 8 a to the power of 5 minus open parentheses negative 2 close parentheses end exponent b to the power of negative 3 minus 1 end exponent c to the power of 1 minus open parentheses negative 3 close parentheses end exponent end cell row cell open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses to the power of negative 1 end exponent end cell equals cell 8 a to the power of 7 b to the power of negative 4 end exponent c to the power of 4 end cell row cell open parentheses fraction numerator 3 straight a to the power of negative 2 end exponent bc to the power of negative 3 end exponent over denominator 24 straight a to the power of 5 straight b to the power of negative 3 end exponent straight c end fraction close parentheses to the power of negative 1 end exponent end cell equals cell fraction numerator 8 straight a to the power of 7 straight c to the power of 4 over denominator b to the power of 4 end fraction end cell row blank blank blank row blank blank blank end table


Oleh karena itu, jawaban yang benar adalah A.

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Rashida Selena Ramadhani

Pembahasan lengkap banget Ini yang aku cari! Mudah dimengerti Bantu banget Makasih ❤️

Batrisyia Priyanda

Makasih ❤️

KeisyaAfzlia

Mudah dimengerti

Ahmad Lafif Arham Ibad

Pembahasan tidak menjawab soal Pembahasan terpotong

Kayla Desvita Larasati

Jawaban tidak sesuai Pembahasan tidak lengkap Pembahasan tidak menjawab soal

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