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Pertanyaan

Bentuk sederhana 4 8 1 3 ​ ⋅ 6 2 3 ​ 6 1 6 3 ​ ⋅ 9 4 ​ ​ = ....

Bentuk sederhana  ....

  1. undefined 

  2. undefined 

  3. undefined 

  4. undefined 

  5. undefined 

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P. Nur

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah E.

jawaban yang benar adalah E.

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Pembahasan

Ingat kembali sifat akar dan sifat bilangan berpangkat: Berdasarkan sifat tersebut maka diperoleh bentuk sederhana: Oleh karena itu, jawaban yang benar adalah E.

Ingat kembali sifat akar dan sifat bilangan berpangkat:

table attributes columnalign right center left columnspacing 0px end attributes row cell a to the power of m over n end exponent end cell equals cell n-th root of a to the power of m end root end cell row cell open parentheses a to the power of m close parentheses to the power of n end cell equals cell a to the power of m cross times n end exponent end cell row cell a to the power of m cross times a to the power of n end cell equals cell a to the power of m plus n end exponent end cell row cell a to the power of m divided by a to the power of n end cell equals cell a to the power of m minus n end exponent end cell end table

Berdasarkan sifat tersebut maka diperoleh bentuk sederhana:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator root index 6 of 16 cubed end root times square root of 9 to the power of 4 end root over denominator fourth root of 81 cubed end root times root index 6 of 2 cubed end root end fraction end cell equals cell fraction numerator 16 to the power of begin display style 3 over 6 end style end exponent times 9 to the power of begin display style 4 over 2 end style end exponent over denominator 81 to the power of begin display style 3 over 4 end style end exponent times 2 to the power of begin display style 3 over 6 end style end exponent end fraction end cell row blank equals cell fraction numerator open parentheses 2 to the power of 4 close parentheses to the power of begin display style 3 over 6 end style end exponent times open parentheses 3 squared close parentheses to the power of begin display style 4 over 2 end style end exponent over denominator open parentheses 3 to the power of 4 close parentheses to the power of begin display style 3 over 4 end style end exponent times 2 to the power of begin display style 3 over 6 end style end exponent end fraction end cell row blank equals cell fraction numerator 2 to the power of begin display style 4 cross times 3 over 6 end style end exponent times 3 to the power of begin display style 2 cross times 2 end style end exponent over denominator 3 to the power of begin display style 4 cross times 3 over 4 end style end exponent times 2 to the power of begin display style 3 over 6 end style end exponent end fraction end cell row blank equals cell fraction numerator 2 to the power of begin display style 12 over 6 end style end exponent times 3 to the power of begin display style 4 end style end exponent over denominator 3 to the power of begin display style 3 end style end exponent times 2 to the power of begin display style 3 over 6 end style end exponent end fraction end cell row blank equals cell 3 to the power of 4 minus 3 end exponent times 2 to the power of 12 over 6 minus 3 over 6 end exponent end cell row blank equals cell 3 times 2 to the power of 9 over 6 end exponent end cell row blank equals cell 3 times 2 to the power of 3 over 2 end exponent end cell row blank equals cell 3 times 2 to the power of 1 plus 1 half end exponent end cell row blank equals cell 3 times 2 times 2 to the power of 1 half end exponent end cell row blank equals cell 6 times 2 to the power of 1 half end exponent end cell row blank equals cell 6 square root of 2 end cell end table 

Oleh karena itu, jawaban yang benar adalah E.

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