Pertanyaan

Bentuk paling sederhana dari adalah ....

Bentuk paling sederhana dari $begin mathsize 14px style open parentheses fraction numerator x y to the power of negative 1 end exponent over denominator x to the power of negative 3 end exponent y cubed end fraction close parentheses to the power of negative 4 end exponent end style$ adalah ....

E. Nur

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Kita akan menggunakan sifat-sifat berikut. Perhatikan perhitungan berikut! Jadi, jawaban yang tepat adalah B.

Kita akan menggunakan sifat-sifat berikut.

Perhatikan perhitungan berikut!

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator x y to the power of negative 1 end exponent over denominator x to the power of negative 3 end exponent y cubed end fraction close parentheses to the power of negative 4 end exponent end cell equals cell open parentheses x to the power of 1 minus open parentheses negative 3 close parentheses end exponent y to the power of negative 1 minus 3 end exponent close parentheses to the power of negative 4 end exponent end cell row cell space space space space space space space space space space space space space space space space space space end cell equals cell open parentheses x to the power of 4 y to the power of negative 4 end exponent close parentheses to the power of negative 4 end exponent end cell row cell space space space space space space space space space space space space space space space space space space end cell equals cell x to the power of 4 times open parentheses negative 4 close parentheses end exponent y to the power of negative 4 times open parentheses negative 4 close parentheses end exponent end cell row cell space space space space space space space space space space space space space space space space space end cell equals cell x to the power of negative 16 end exponent y to the power of 16 end cell row cell space space space space space space space space space space space space space space space space space space end cell equals cell y to the power of 16 over x to the power of 16 end cell row cell space space space space space space space space space space space space space space space space space space end cell equals cell box enclose open parentheses y over x close parentheses to the power of 16 end enclose end cell end table end style$

Jadi, jawaban yang tepat adalah B.