Pertanyaan

= ....

K. Nurul

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

Pembahasan

Dengan menggunakan sifat bilangan berpangkat, kita peroleh Jadi, jawaban yang tepat adalah A.

Dengan menggunakan sifat bilangan berpangkat, kita peroleh

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 3 a to the power of 4 close parentheses cubed over open parentheses 2 a to the power of negative 2 end exponent close parentheses to the power of negative 1 end exponent end cell equals cell fraction numerator 3 cubed open parentheses a to the power of 4 close parentheses cubed over denominator 2 to the power of negative 1 end exponent open parentheses a to the power of negative 2 end exponent close parentheses to the power of negative 1 end exponent end fraction end cell row blank equals cell fraction numerator 3 cubed a to the power of 4 cross times 3 end exponent over denominator 2 to the power of negative 1 end exponent a to the power of negative 2 cross times left parenthesis negative 1 right parenthesis end exponent end fraction end cell row blank equals cell fraction numerator 3 cubed a to the power of 12 over denominator 2 to the power of negative 1 end exponent a squared end fraction end cell row blank equals cell fraction numerator 2 to the power of 1 space 3 cubed space a to the power of 12 over denominator a squared end fraction end cell row blank equals cell 2 cross times 27 a to the power of 12 minus 2 end exponent end cell row blank equals cell 54 a to the power of 10 end cell end table end style$

Jadi, jawaban yang tepat adalah A.