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Anda ingin membuat larutan penyangga ber-pH 8 dari...

Anda ingin membuat larutan penyangga ber-pH 8 dari larutan begin mathsize 14px style N H subscript 3 space 0 comma 2 space M space left parenthesis Kb equals 1 comma 8 cross times 10 to the power of negative sign 5 end exponent right parenthesis end style dan begin mathsize 14px style N H subscript 4 Cl space 0 comma 4 space M end style. Bila begin mathsize 14px style N H subscript 3 end style yang digunakan sebanyak 100 mL, berapakah volume undefined yang diperlukan?undefined 

Jawaban:

Larutan penyangga di atas termasuk larutan penyangga basa karena pada reaksinya menghasilkan ion begin mathsize 14px style O H to the power of minus sign end style.

begin mathsize 14px style N H subscript 3 open parentheses aq close parentheses equilibrium N H subscript 4 to the power of plus sign left parenthesis italic a italic q right parenthesis plus O H to the power of minus sign left parenthesis italic a italic q right parenthesis N H subscript 4 Cl left parenthesis italic a italic q right parenthesis yields N H subscript 4 to the power of plus sign left parenthesis italic a italic q right parenthesis plus Cl to the power of minus sign left parenthesis italic a italic q right parenthesis end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell mmol space N H subscript 4 O H end cell equals cell space V space N H subscript 4 O H cross times M space N H subscript 4 O H end cell row cell mmol space N H subscript 4 O H end cell equals cell 100 space mL cross times 0 comma 2 space mmol forward slash mL end cell row cell mmol space N H subscript 4 O H end cell equals cell 20 space mmol end cell row blank blank blank row pH equals 8 row pOH equals cell 14 minus sign pH end cell row pOH equals cell 14 minus sign 8 end cell row pOH equals 6 row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 6 end exponent space M end cell row blank blank blank row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript italic b cross times fraction numerator mmol space basa space le mah over denominator mmol space garam end fraction end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell K subscript italic b cross times fraction numerator mmol space N H subscript 4 O H over denominator mmol space N H subscript 4 Cl end fraction end cell row cell 10 to the power of negative sign 6 end exponent end cell equals cell 1 comma 8 cross times 10 to the power of negative sign 5 end exponent cross times fraction numerator 20 space mmol over denominator mmol space space N H subscript 4 Cl end fraction end cell row cell mmol space space N H subscript 4 Cl end cell equals cell fraction numerator 1 comma 8 cross times 10 to the power of negative sign 5 end exponent cross times 20 space mmol over denominator 10 to the power of negative sign 6 end exponent end fraction end cell row cell mmol space N H subscript 4 Cl end cell equals cell 360 space mmol end cell row cell mmol space N H subscript 4 Cl end cell equals cell V space N H subscript 4 Cl cross times M space N H subscript 4 Cl end cell row cell 360 space mmol end cell equals cell V space N H subscript 4 Cl cross times 0 comma 4 space mmol space mL to the power of negative sign 1 end exponent end cell row cell V space N H subscript 4 Cl end cell equals cell fraction numerator 360 space mmol over denominator 0 comma 4 space mmol space mL to the power of negative sign 1 end exponent end fraction end cell row cell V space N H subscript 4 Cl end cell equals cell 900 space mL end cell end table end style 

Jadi volume begin mathsize 14px style N H subscript bold 4 Cl end style yang harus ditambahkan adalah 900 mL.undefined 

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