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Pertanyaan

S u k u ban y ak f ( x ) jika d iba g i x 2 + x − 2 s i s a p e mba g iann y a ( 5 x + 1 ) d an jika f ( x ) d iba g i ( x 2 − 5 x − 6 ) s i s a p e mba g iann y a ( 4 x − 1 ) . S i s a p e mba g ian f ( x ) o l e h ( x 2 − 4 x − 12 ) a d a l ah ....

  1. 4 x plus 1

  2. 4 x minus 1

  3. 1 minus 4 x

  4. x minus 4

  5. x plus 4

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Master Teacher

Jawaban terverifikasi

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Pembahasan

S i s a space p e m b a g i a n space colon space S left parenthesis x right parenthesis equals a x plus b J i k a space fraction numerator f left parenthesis x right parenthesis over denominator left parenthesis x squared plus x minus 2 right parenthesis end fraction space space s i s a space left parenthesis 5 x plus 1 right parenthesis space S left parenthesis negative 2 right parenthesis equals 5 left parenthesis negative 2 right parenthesis plus 1 space minus 2 a plus b equals negative 9 space... space left parenthesis i right parenthesis S left parenthesis 1 right parenthesis equals 5 left parenthesis 1 right parenthesis plus 1 space a plus b equals 6 space... space left parenthesis i i right parenthesis  J i k a space fraction numerator f left parenthesis x right parenthesis over denominator left parenthesis x squared plus 5 x minus 6 right parenthesis end fraction space space s i s a space left parenthesis 4 x plus 1 right parenthesis fraction numerator f left parenthesis x right parenthesis over denominator left parenthesis x minus 6 right parenthesis left parenthesis x plus 1 right parenthesis end fraction space s i s a n y a space left parenthesis 4 x minus 1 right parenthesis S left parenthesis 6 right parenthesis equals 4 left parenthesis 6 right parenthesis minus 1 space 6 a plus b equals 23 space... left parenthesis i i i right parenthesis  S left parenthesis negative 1 right parenthesis equals 4 left parenthesis negative 1 right parenthesis minus 1 space minus a plus b equals negative 5... space left parenthesis i v right parenthesis  S i s a space p e m b a g i a n space f left parenthesis x right parenthesis space o l e h space left parenthesis x squared minus 4 x minus 12 right parenthesis equals left parenthesis x minus 6 right parenthesis left parenthesis x plus 2 right parenthesis space a d a l a h space colon S left parenthesis 6 right parenthesis equals space space space 6 a plus b equals 23 space S left parenthesis negative 2 right parenthesis equals space space minus 2 a plus b equals negative 9 space space minus space 8 a equals 32 a equals 4 J i k a space a equals 4 comma space m a k a space minus 2 left parenthesis 4 right parenthesis plus b equals negative 9 space space space space rightwards arrow space space space space b equals negative 1 space J a d i space s i s a n y a space a d a l a h space S left parenthesis x right parenthesis equals a x plus b equals 4 x minus 1

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J ika f ( x ) = x 3 + ( 5 − n ) x 2 + 2 x + 2 n − 1 d iba g i ( x − 2 ) maka s i s a p e mba g iann y a a d a l ah 27. J ika f ( x ) d iba g i ( x + 2 ) maka s i s a p e mba g iann y a a d a l ah ....

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