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J ika f ( x ) = x 3 + ( 5 − n ) x 2 + 2 x + 2 n − 1 d iba g i ( x − 2 ) maka s i s a p e mba g iann y a a d a l ah 27. J ika f ( x ) d iba g i ( x + 2 ) maka s i s a p e mba g iann y a a d a l ah ....

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f left parenthesis x right parenthesis equals x cubed plus left parenthesis 5 minus n right parenthesis space x squared plus 2 x plus 2 n minus 1 space d i b a g i space left parenthesis x minus 2 right parenthesis space m a k a space s i s a space p e m b a g i a n n y a space a d a l a h space 27 space a r t i n y a space colon f left parenthesis 2 right parenthesis equals 27 space 2 cubed plus left parenthesis 5 minus n right parenthesis space left parenthesis 2 right parenthesis squared plus 2 left parenthesis 2 right parenthesis plus 2 n minus 1 equals 27 space 8 plus 20 minus 4 n plus 4 plus 2 n minus 1 equals 27 space 31 minus 2 n equals 27 space 2 n equals 27 minus 31 space n equals 2 S e h i n g g a space d i p e r o l e h space f left parenthesis x right parenthesis equals x cubed plus 3 x squared plus 2 x plus 3 J a d i space f left parenthesis x right parenthesis space d i b a g i space left parenthesis x plus 2 right parenthesis comma space s i s a n y a space a d a l a h space colon f left parenthesis negative 2 right parenthesis equals left parenthesis negative 2 right parenthesis cubed plus 3 left parenthesis negative 2 right parenthesis squared plus 2 left parenthesis negative 2 right parenthesis plus 3 equals negative 8 plus 12 minus 4 plus 3 equals 3 space

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J ika s u k u ban y ak f ( x ) = a x − b d iba g i d e n g an ( 2 x − 6 ) , maka s i s a p e mba g iann y a s ama d e n g an ....

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