Pertanyaan

J ika f ( x ) = x + x 1 ​ d an g ( x ) = x − x 1 ​ maka g { f ( x )} a d a l ah ...

  1. x squared minus 1

  2. fraction numerator x squared plus 1 over denominator x end fraction minus fraction numerator x over denominator x squared minus 1 end fraction

  3. fraction numerator x squared minus 1 over denominator x end fraction minus fraction numerator x over denominator x squared plus 1 end fraction

  4. 2x

  5. fraction numerator x squared plus 1 over denominator x end fraction minus fraction numerator x over denominator x squared plus 1 end fraction

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f left parenthesis x right parenthesis equals x plus 1 over x space d a n space g left parenthesis x right parenthesis equals x minus 1 over x  left curly bracket g f left parenthesis x right parenthesis right curly bracket equals g o f  space space space space space space space space space space space space equals open parentheses x plus 1 over x close parentheses minus fraction numerator 1 over denominator open parentheses x plus begin display style 1 over x end style close parentheses end fraction  space space space space space space space space space space space space equals fraction numerator open parentheses x plus begin display style 1 over x end style close parentheses squared minus 1 over denominator open parentheses x plus 1 over x close parentheses end fraction  space space space space space space space space space space space space equals fraction numerator open parentheses fraction numerator x squared plus 1 over denominator x end fraction close parentheses squared minus 1 over denominator open parentheses fraction numerator x squared plus 1 over denominator x end fraction close parentheses end fraction  space space space space space space space space space space space equals fraction numerator x squared minus 1 over denominator x end fraction minus fraction numerator x over denominator x squared plus 1 end fraction

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