Pertanyaan

J ika f ( x ) = x 1 d an g ( x ) = 2 x − 1 maka ( f o g ) − 1 ( x ) a d a l ah ...

$J ika f (x) = \frac{1}{x} d an g (x) = 2 x - 1 maka (f o g)^{- 1} (x) a d a l ah ...$

$fraction numerator 2 x minus 1 over denominator x end fraction$
$fraction numerator x over denominator 2 x minus 1 end fraction$
$fraction numerator x plus 1 over denominator 2 x end fraction$
$fraction numerator 2 x over denominator x plus 1 end fraction$
$fraction numerator 2 x minus 1 over denominator 2 end fraction$

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Habis dalam

Klaim

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

$f left parenthesis x right parenthesis equals 1 over x g left parenthesis x right parenthesis equals 2 x minus 1 left parenthesis f o g right parenthesis left parenthesis x right parenthesis equals fraction numerator 1 over denominator 2 x minus 1 end fraction y equals fraction numerator 1 over denominator 2 x minus 1 end fraction 2 x y minus y equals 1 2 x y equals y plus 1 x equals fraction numerator y plus 1 over denominator 2 y end fraction left parenthesis f o g right parenthesis to the power of negative 1 end exponent left parenthesis x right parenthesis equals fraction numerator x plus 1 over denominator 2 x end fraction$