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J ika f ( x ) = x 2 + 1 ​ d an ( f o g ) ( x ) x + 1 1 ​ x 2 − 4 x + 5 ​ , maka g ( x − 3 ) = ...

  1. fraction numerator 1 over denominator x minus 5 end fraction

  2. fraction numerator 1 over denominator x plus 1 end fraction

  3. fraction numerator 1 over denominator x minus 1 end fraction

  4. fraction numerator 1 over denominator x minus 3 end fraction

  5. fraction numerator 1 over denominator x plus 3 end fraction

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D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

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Pembahasan

f left parenthesis x right parenthesis equals square root of x squared plus 1 end root space d a n  left parenthesis f o g right parenthesis left parenthesis x right parenthesis equals fraction numerator 1 over denominator x plus 1 end fraction square root of x squared minus 4 x plus 5 end root  left parenthesis f o g right parenthesis left parenthesis x right parenthesis equals f left parenthesis g left parenthesis x right parenthesis right parenthesis  m i s a l space g left parenthesis x right parenthesis space equals space a comma space m a k a colon  f space left parenthesis g left parenthesis x right parenthesis right parenthesis equals left parenthesis f o g right parenthesis left parenthesis x right parenthesis  square root of a squared plus 1 end root equals fraction numerator 1 over denominator x minus 2 end fraction square root of x squared minus 4 x plus 5 end root  a squared plus 1 equals fraction numerator x squared minus 4 x plus 5 over denominator left parenthesis x minus 2 right parenthesis squared end fraction  a squared equals fraction numerator x squared minus 4 x plus 5 over denominator left parenthesis x minus 2 right parenthesis squared end fraction minus 1  a squared equals fraction numerator x squared minus 4 x plus 5 minus left parenthesis x squared minus 4 x plus 5 right parenthesis over denominator left parenthesis x minus 2 right parenthesis squared end fraction  a squared equals fraction numerator 1 over denominator left parenthesis x minus 2 right parenthesis squared end fraction  a equals fraction numerator 1 over denominator x minus 2 end fraction  m a k a colon  g left parenthesis x right parenthesis equals fraction numerator 1 over denominator x minus 2 end fraction  g left parenthesis x minus 3 right parenthesis equals fraction numerator 1 over denominator x minus 3 minus 2 end fraction  g left parenthesis x minus 3 right parenthesis equals fraction numerator 1 over denominator x minus 5 end fraction

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Diketahui fungsi f ( x ) = 1 + x 2 ​ dan ( f ∘ g ) ( x ) = x − 2 1 ​ x 2 − 4 x + 5 ​ . Rumus fungsi g ( x + 3 ) = ...

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