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Pertanyaan

Diketahui x 1 ​ dan x 2 ​ adalah akar − akar persamaan kuadrat x 2 − 7 x + 10 = 0. Nilai dari x 1 2 ​ + x 2 2 ​ − x 1 ​ x 2 ​ = ....

  1. -23

  2. -3

  3. 10

  4. 19

  5. 23

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F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

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Pembahasan

U n t u k space p e r s a m a a n space k u a d r a t space a x squared plus b x plus c equals 0 space y a n g space m e m i l i k i space a k a r space x subscript 1 d a n space x subscript 2 comma m a k a  x subscript 1 plus x subscript 2 equals fraction numerator negative b over denominator a end fraction  x subscript 1 x subscript 2 equals c over a

P e r s a m a a n space k u a d r a t space x squared minus 7 x plus 10 equals 0 space d e n g a n space a equals 1 comma space b equals negative 7 space d a n space c equals 10 comma space m e m i l i k i space a k a r minus a k a r space x subscript 1 d a n space x subscript 2 comma space m a k a  x subscript 1 plus x subscript 2 equals fraction numerator negative b over denominator a end fraction equals fraction numerator negative left parenthesis negative 7 right parenthesis over denominator 1 end fraction equals 7  x subscript 1 x subscript 2 equals c over a equals 10 over 1 equals 10

bold italic L bold italic a bold italic g bold italic k bold italic a bold italic h bold space bold italic p bold italic e bold italic r bold italic t bold italic a bold italic m bold italic a bold space bold colon bold thin space bold italic B bold italic e bold italic n bold italic t bold italic u bold italic k bold italic l bold italic a bold italic h bold space x subscript 1 superscript 2 plus x subscript 2 superscript 2 minus x subscript 1 x subscript 2 bold space bold italic k bold italic e bold italic d bold italic a bold italic l bold italic a bold italic m bold space bold italic b bold italic e bold italic n bold italic t bold italic u bold italic k space x subscript 1 plus x subscript 2 bold space bold italic d bold italic a bold italic n space x subscript 1 x subscript 2  left parenthesis x subscript 1 plus x subscript 2 right parenthesis squared equals x subscript 1 squared plus x subscript 2 squared plus 2 x subscript 1 x subscript 2  x subscript 1 squared plus x subscript 2 squared equals left parenthesis x subscript 1 plus x subscript 2 right parenthesis squared minus 2 x subscript 1 x subscript 2    bold italic L bold italic a bold italic n bold italic g bold italic k bold italic a bold italic h bold space bold italic k bold italic e bold italic d bold italic u bold italic a bold space bold colon bold thin space bold italic K bold italic e bold italic m bold italic u bold italic d bold italic i bold italic a bold italic n bold space bold italic s bold italic u bold italic b bold italic s bold italic t bold italic i bold italic t bold italic u bold italic s bold italic i bold italic k bold italic a bold italic n space x subscript 1 squared plus x subscript 2 squared space bold italic k bold italic e bold italic d bold italic a bold italic l bold italic a bold italic m bold space bold italic b bold italic e bold italic n bold italic t bold italic u bold italic k bold space bold italic s bold italic o bold italic a bold italic l  x subscript 1 squared plus x subscript 2 squared minus x subscript 1 x subscript 2  equals left square bracket left parenthesis x subscript 1 plus x subscript 2 right parenthesis squared minus 2 x subscript 1 x subscript 2 right square bracket minus x subscript 1 x subscript 2  equals left parenthesis x subscript 1 plus x subscript 2 right parenthesis squared minus 3 x subscript 1 x subscript 2

bold italic L bold italic a bold italic n bold italic g bold italic k bold italic a bold italic h bold space bold italic k bold italic e bold italic t bold italic i bold italic g bold italic a bold space bold thin space bold colon bold space bold italic S bold italic u bold italic b bold italic s bold italic t bold italic i bold italic t bold italic u bold italic s bold italic i bold italic k bold italic a bold italic n space x subscript 1 plus x subscript 2 equals 7 space d a n space x subscript 1 x subscript 2 equals 10 space bold italic k bold italic e bold italic d bold italic a bold italic l bold italic a bold italic m bold space bold italic p bold italic e bold italic r bold italic s bold italic a bold italic m bold italic a bold italic a bold italic n  x subscript 1 squared plus x subscript 2 squared minus x subscript 1 x subscript 2  equals left parenthesis x subscript 1 plus x subscript 2 right parenthesis squared minus 3 x subscript 1 x subscript 2  equals left parenthesis 7 right parenthesis squared minus 3 left parenthesis 10 right parenthesis  equals 49 minus 30  equals 19

 

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Pertanyaan serupa

Akar-akar persamaan x 2 + ( a − 1 ) x + 2 = 0 adalah α dan β . Jika α = 2 β dan a > 0 maka nilai a=.....

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