Roboguru

Pertanyaan

A k a r minus a k a r space p e r s a m a a n space x squared plus left parenthesis a minus 1 right parenthesis x plus 2 equals 0 space a d a l a h space alpha space d a n space beta. space J i k a space alpha equals 2 beta space d a n space a greater than 0 comma space m a k a space n i l a i space space a equals space.... space

  1. 2

  2. 3

  3. 4

  4. 6

  5. 8

F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

Pembahasan

P e r s a m a a n space k u a d r a t space x squared plus left parenthesis a minus 1 right parenthesis x plus 2 equals 0 space m e m i l i k i space a k a r – a k a r space alpha space d a n space beta comma d i m a n a space alpha equals 2 beta comma space b e r a r t i  alpha beta equals c over a  2 beta beta equals 2 over 1  2 beta squared equals 2  beta squared equals 1  beta equals plus-or-minus 1    M a k a space  alpha equals 2 left parenthesis 1 right parenthesis equals 2 space a t a u space alpha equals 2 left parenthesis negative 1 right parenthesis equals negative 2

9

0.0 (0 rating)

Pertanyaan serupa

Akar−akarpersamaanx2+(a−1)x+2=0adalahαdanβ.Jikaα=2βdana>0makanilaia=....

8

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia