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Pertanyaan

J u m l ah d ere t t ak hin gg a d a r i 1 + 2 1 ​ + 4 1 ​ + 8 1 ​ + ... a d a l ah ...

  1. 2

  2. 31 over 16

  3. 30 over 16

  4. 31 over 32

  5. 30 over 32

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I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Pembahasan

a equals 1  r equals fraction numerator 1 divided by 2 over denominator 1 end fraction equals fraction numerator 1 divided by 4 over denominator 1 divided by 2 end fraction equals... equals 1 half  J u m l a h space d e r e t space g e o m e t r i space t a k space h i n g g a space m e m e n u h i  S subscript infinity equals fraction numerator a over denominator 1 minus r apostrophe end fraction open vertical bar r close vertical bar less than 1  S subscript infinity equals fraction numerator 1 over denominator 1 minus begin display style 1 half end style end fraction  S subscript infinity equals fraction numerator 1 over denominator 1 divided by 2 end fraction  S subscript infinity equals 1 left parenthesis 2 right parenthesis equals 2

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Hasil dari 1 − 4 2 ​ + 16 3 ​ − 64 4 ​ + 256 5 ​ − … adalah ....

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