Pertanyaan

J ika ma t r ik s A = ( − 1 − 3 2 4 ) , B = ( 2 5 − 3 − 4 ) , d an X = A + B , in v ers ma t r ik s X a d a l ah ....

$J ika ma t r ik s A = (- 1 - 3 24), B = (25 - 3 - 4), d an X = A + B, in v ers ma t r ik s X a d a l ah ....$

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

$O p e r a s i k a n space m a t r i k s space u n t u k space m e n d a p a t k a n space m a t r i k s space X X equals A plus B X equals open parentheses table row cell negative 1 end cell 2 row cell negative 3 end cell 4 end table close parentheses plus open parentheses table row 2 cell negative 3 end cell row 5 cell negative 4 end cell end table close parentheses C equals open parentheses table row 1 cell negative 1 end cell row 2 0 end table close parentheses I n v e r s space d a r i space m a t r i k s space open parentheses table row a b row c d end table close parentheses rightwards arrow with i n v e r s on top fraction numerator 1 over denominator a d minus b c end fraction open parentheses table row d cell negative b end cell row cell negative c end cell a end table close parentheses M a k a space i n v e r s space d a r i space m a t r i k s space X X to the power of negative 1 end exponent equals fraction numerator 1 over denominator left parenthesis 1.0 right parenthesis minus left parenthesis left parenthesis negative 1 right parenthesis. left parenthesis 2 right parenthesis right parenthesis end fraction open parentheses table row 0 1 row cell negative 2 end cell 1 end table close parentheses X to the power of negative 1 end exponent equals 1 half open parentheses table row 0 1 row cell negative 2 end cell 1 end table close parentheses$