Roboguru

Pertanyaan

Nilai space limit as x rightwards arrow 0 of fraction numerator 1 minus cos squared 2 x over denominator x sin 2 x end fraction space equals space....

  1. 4

  2. 2

  3. 0

  4. -2

  5. -4

F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

Pembahasan

limit as x rightwards arrow 0 of fraction numerator 1 minus cos squared 2 x over denominator x space sin 2 x end fraction space equals space limit as x rightwards arrow 0 of fraction numerator begin display style sin squared 2 x end style over denominator begin display style x space sin 2 x end style end fraction space equals space limit as x rightwards arrow 0 of fraction numerator begin display style sin 2 x space sin 2 x end style over denominator begin display style x space sin 2 x end style end fraction space equals space 2

110

5.0 (3 rating)

Pertanyaan serupa

Nilai x→0lim​xsin2x1−cos22x​=...

35

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia