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Pertanyaan

x → 0 lim ​ x 2 1 − cos x ​ = ...

   

  1.  0

  2.  0 comma 125 

  3. 0 comma 25 

  4.  0 comma 5  

  5. 1  

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah D.

jawaban yang benar adalah D.

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Pembahasan

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Ingat kembali identitas trigonometri dan limit fungsi trigonometri berikut. Dari aturan di atas, maka diperoleh Dengan demikian, . Jadi, jawaban yang benar adalah D.

Ingat kembali identitas trigonometri dan limit fungsi trigonometri berikut.

  • sin squared x plus cos squared x equals 1

 

  • limit as x rightwards arrow c of space f left parenthesis x right parenthesis times g left parenthesis x right parenthesis equals limit as x rightwards arrow c of space f left parenthesis x right parenthesis times limit as x rightwards arrow c of space g left parenthesis x right parenthesis

 

  • limit as x rightwards arrow 0 of fraction numerator sin space a x over denominator b x end fraction equals limit as x rightwards arrow 0 of fraction numerator space a x over denominator sin space b x end fraction equals a over b

Dari aturan di atas, maka diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 0 of fraction numerator 1 minus cos space x over denominator x squared end fraction end cell equals cell limit as x rightwards arrow 0 of fraction numerator 1 minus cos space x over denominator x squared end fraction times fraction numerator 1 plus cos space x over denominator 1 plus cos space x end fraction end cell row blank equals cell limit as x rightwards arrow 0 of fraction numerator 1 minus cos squared x over denominator x squared left parenthesis 1 plus cos space x right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 0 of fraction numerator 1 minus left parenthesis 1 minus sin squared x right parenthesis over denominator x squared left parenthesis 1 plus cos space x right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 0 of fraction numerator 1 minus 1 plus sin squared x right parenthesis over denominator x squared left parenthesis 1 plus cos space x right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 0 of fraction numerator sin squared x over denominator x squared left parenthesis 1 plus cos space x right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 0 of fraction numerator sin space x times sin space x over denominator x times x end fraction times fraction numerator 1 over denominator left parenthesis 1 plus cos space x right parenthesis end fraction end cell row blank equals cell limit as x rightwards arrow 0 of space fraction numerator sin space x over denominator x end fraction times space limit as x rightwards arrow 0 of space fraction numerator sin space x over denominator x end fraction times limit as x rightwards arrow 0 of space fraction numerator 1 over denominator left parenthesis 1 plus cos space x right parenthesis end fraction end cell row blank equals cell 1 times 1 times limit as x rightwards arrow 0 of fraction numerator 1 over denominator 1 plus cos space x end fraction end cell row blank equals cell fraction numerator 1 over denominator 1 plus cos space 0 end fraction end cell row blank equals cell fraction numerator 1 over denominator 1 plus 1 end fraction end cell row blank equals cell 1 half end cell row blank equals cell 0 comma 5 end cell end table     

Dengan demikian, limit as x rightwards arrow 0 of fraction numerator 1 minus cos space x over denominator x squared end fraction equals 0 comma 5.

Jadi, jawaban yang benar adalah D.

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