Pertanyaan

D ik e t ah u i 2 lo g 3 = a d an 2 lo g 5 = b . N i l ai d a r i 9 lo g 150 d a l am a d an b a d a l ah ...

$D ik e t ah u i^{2} lo g 3 = a d an^{2} lo g 5 = b . N i l ai d a r i^{9} lo g 150 d a l am a d an b a d a l ah ...$

$fraction numerator 1 plus 2 b over denominator 2 end fraction$
$fraction numerator 2 a over denominator 1 plus 2 b end fraction$
$fraction numerator 1 plus a plus 2 b over denominator 2 a end fraction$
$fraction numerator 1 plus a plus b over denominator a end fraction$

M. Mariyam

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

$table row 9 row space end table log invisible function application 150 equals fraction numerator table row 2 row space end table log invisible function application space 150 over denominator table row 2 row space end table log invisible function application space 9 end fraction equals fraction numerator table row 2 row space end table log invisible function application space left parenthesis 2 cross times 3 cross times 5 squared right parenthesis over denominator table row 2 row space end table log invisible function application space 3 squared end fraction equals fraction numerator table row 2 row space end table log invisible function application space open parentheses 2 close parentheses plus table row 2 row space end table log invisible function application space 3 plus table row 2 row space end table log invisible function application space 5 squared over denominator 2 times table row 2 row space end table log invisible function application space 3 end fraction equals fraction numerator table row 2 row space end table log invisible function application space open parentheses 2 close parentheses plus table row 2 row space end table log invisible function application space 3 plus 2 times table row 2 row space end table log invisible function application space 5 over denominator 2 times table row 2 row space end table log invisible function application space 3 end fraction equals fraction numerator 1 invisible function application space plus a plus 2 b over denominator 2 a end fraction$