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Pertanyaan

N i l ai d a r i x → 2 lim ​ x 2 − 4 ( 2 x + 1 ) tan ( x − 2 ) ​ = ...

  1. 5

  2. 2,5

  3. 2

  4. 1,5

  5. 1,25

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F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Pembahasan

limit as x rightwards arrow p of fraction numerator left parenthesis 2 x plus 1 right parenthesis space space tan invisible function application left parenthesis x minus 2 right parenthesis over denominator x squared minus 4 end fraction  equals limit as x rightwards arrow 2 of fraction numerator left parenthesis 2 x plus 1 right parenthesis space space tan invisible function application left parenthesis x minus 2 right parenthesis over denominator left parenthesis x plus 2 right parenthesis left parenthesis x minus 2 right parenthesis end fraction  equals limit as x rightwards arrow 2 of left parenthesis 2 x plus 1 right parenthesis. limit as x rightwards arrow 2 of fraction numerator tan begin display style invisible function application end style begin display style left parenthesis end style begin display style x end style begin display style minus end style begin display style 2 end style begin display style right parenthesis end style over denominator left parenthesis x plus 2 right parenthesis left parenthesis x minus 2 right parenthesis end fraction  equals limit as x rightwards arrow 2 of left parenthesis 2 x plus 1 right parenthesis. limit as x rightwards arrow 2 of fraction numerator 1 over denominator left parenthesis x plus 2 right parenthesis end fraction  equals left parenthesis 2 left parenthesis 2 right parenthesis plus 1 right parenthesis. fraction numerator begin display style 1 end style over denominator 2 plus 2 end fraction  equals 5 over 4  equals 1 comma 25

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Nilai x → 3 π ​ lim ​ sin ( 3 x − π ) tan ( 3 x − π ) cos ( 2 x ) ​ adalah ...

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