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x → 0 lim ​ tx ⋅ sin 2 x 1 − cos x ​ = ....

 

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N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

hasil limit tersebut adalah .

hasil limit tersebut adalah fraction numerator 1 over denominator 4 t end fraction.

Pembahasan

Pembahasan
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Ingat kembali: Maka: Jadi, hasil limit tersebut adalah .

Ingat kembali:

1 minus cos space straight x equals 2 times sin squared open parentheses 1 half straight x close parentheses 

Maka:

limit as straight x rightwards arrow 0 of space fraction numerator 1 minus cos space straight x over denominator tx times sin space 2 straight x end fraction equals limit as straight x rightwards arrow 0 of space fraction numerator 2 times sin squared open parentheses begin display style 1 half straight x end style close parentheses over denominator tx times sin space 2 straight x end fraction space space space space space space space space space space space space space space space space space space space space space space equals limit as straight x rightwards arrow 0 of space fraction numerator 2 times sin space open parentheses begin display style 1 half straight x end style close parentheses times sin space open parentheses begin display style 1 half straight x end style close parentheses over denominator tx times sin space 2 straight x end fraction space space space space space space space space space space space space space space space space space space space space space space equals limit as straight x rightwards arrow 0 of space 2 over straight t times fraction numerator sin space open parentheses begin display style 1 half straight x end style close parentheses over denominator straight x end fraction times fraction numerator sin space open parentheses begin display style 1 half straight x end style close parentheses over denominator sin space 2 straight x end fraction space space space space space space space space space space space space space space space space space space space space space space equals 2 over straight t times 1 half times fraction numerator begin display style 1 half end style over denominator 2 end fraction space space space space space space space space space space space space space space space space space space space space space space equals 2 over straight t times 1 half times 1 fourth space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 2 over denominator 8 straight t end fraction space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 1 over denominator 4 straight t end fraction space space space space space space space space space space space space space space space space space space space space space space 

Jadi, hasil limit tersebut adalah fraction numerator 1 over denominator 4 t end fraction.

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