x→10lim​x−10x−1​−3​

Pertanyaan

begin mathsize 14px style limit as x rightwards arrow 10 of fraction numerator square root of x minus 1 end root minus 3 over denominator x minus 10 end fraction end style

D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

jawabannya adalah undefined

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 10 of fraction numerator square root of x minus 1 end root minus 3 over denominator x minus 10 end fraction end cell row blank equals cell limit as x rightwards arrow 10 of fraction numerator square root of x minus 1 end root minus 3 over denominator x minus 10 end fraction cross times fraction numerator square root of x minus 1 end root plus 3 over denominator square root of x minus 1 end root plus 3 end fraction end cell row blank equals cell limit as x rightwards arrow 10 of fraction numerator x minus 1 minus 9 over denominator open parentheses x minus 10 close parentheses. open parentheses square root of x minus 1 end root plus 3 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 10 of fraction numerator up diagonal strike x minus 10 end strike over denominator up diagonal strike open parentheses x minus 10 close parentheses end strike. open parentheses square root of x minus 1 end root plus 3 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 10 of fraction numerator 1 over denominator open parentheses square root of x minus 1 end root plus 3 close parentheses end fraction end cell row blank equals cell fraction numerator 1 over denominator open parentheses square root of 10 minus 1 end root plus 3 close parentheses end fraction end cell row blank equals cell 1 over 6 end cell end table end style

Jadi, jawabannya adalah undefined

75

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