x→9lim​x−9x​−3​

Pertanyaan

begin mathsize 14px style limit as x rightwards arrow 9 of fraction numerator square root of x minus 3 over denominator x minus 9 end fraction end style

D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

jawabannya adalah begin mathsize 14px style bold 1 over bold 6 end style

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 9 of fraction numerator square root of x minus 3 over denominator x minus 9 end fraction end cell equals cell limit as x rightwards arrow 9 of fraction numerator square root of x minus 3 over denominator x minus 9 end fraction cross times fraction numerator square root of x plus 3 over denominator square root of x plus 3 end fraction end cell row blank equals cell limit as x rightwards arrow 9 of fraction numerator up diagonal strike open parentheses x minus 9 close parentheses end strike over denominator up diagonal strike open parentheses x minus 9 close parentheses end strike. open parentheses square root of x plus 3 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 9 of fraction numerator 1 over denominator open parentheses square root of x plus 3 close parentheses end fraction end cell row blank equals cell fraction numerator 1 over denominator square root of 9 plus 3 end fraction end cell row blank equals cell 1 over 6 end cell end table end style

Jadi, jawabannya adalah begin mathsize 14px style bold 1 over bold 6 end style

184

4.8 (9 rating)

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