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Pertanyaan

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 3 to the power of 7 cross times 3 squared over denominator 3 cubed end fraction end cell equals cell... end cell end table 

Pembahasan Soal:

Sesuai dengan sifat perkalian dan pembagian bilangan berpangkat sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 3 to the power of 7 cross times 3 squared over denominator 3 cubed end fraction end cell equals cell 3 to the power of open parentheses 7 plus 2 close parentheses end exponent over 3 cubed end cell row blank equals cell 3 to the power of 9 over 3 cubed end cell row blank equals cell 3 to the power of open parentheses 9 minus 3 close parentheses end exponent end cell row blank equals cell 3 to the power of 6 end cell row blank equals 729 end table 

Jadi, table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 3 to the power of 7 cross times 3 squared over denominator 3 cubed end fraction end cell equals 729 end table.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

K. Putri

Mahasiswa/Alumni Universitas Pendidikan Ganesha

Terakhir diupdate 02 Mei 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Bentuk sederhana dari  adalah ...

Pembahasan Soal:

Sifat Bilangan Berpangkat.

table attributes columnalign right center left columnspacing 0px end attributes row cell a to the power of negative m end exponent end cell equals cell 1 over a to the power of m end cell row cell a to the power of m over a to the power of n end cell equals cell a to the power of m minus n end exponent end cell row cell open parentheses a to the power of m close parentheses to the power of n end cell equals cell a to the power of m times n end exponent end cell end table 

Diketahui fraction numerator 3 open parentheses a b close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction.

Bentuk sederhana dari fraction numerator 3 open parentheses a b close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction adalah:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 3 open parentheses a b close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction end cell equals cell fraction numerator 3 open parentheses a to the power of 1 b to the power of 1 close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction end cell row blank equals cell 1 third times fraction numerator a squared b squared c to the power of negative 3 end exponent over denominator a to the power of negative 1 end exponent b to the power of 5 end fraction end cell row blank equals cell 1 third times fraction numerator a to the power of 2 minus open parentheses negative 1 close parentheses end exponent over denominator b to the power of 5 minus 2 end exponent c cubed end fraction end cell row blank equals cell 1 third times fraction numerator a cubed over denominator b cubed c cubed end fraction end cell row blank equals cell 1 third open parentheses fraction numerator a over denominator b c end fraction close parentheses cubed end cell end table 

Sehingga, Error converting from MathML to accessible text..

Jadi, jawaban yang tepat adalah E.

0

Roboguru

Bentuk sederhana dari  adalah ...

Pembahasan Soal:

Gunakan sifat-sifat operasi hitung bilangan berpangkat untuk mengerjakan soal tersebut.


table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator a to the power of negative 2 end exponent times b to the power of 8 times c to the power of 10 over denominator a to the power of 12 times b to the power of negative 4 end exponent times c to the power of 6 end fraction close parentheses end cell equals cell open parentheses a to the power of negative 2 minus 12 end exponent times b to the power of 8 minus left parenthesis negative 4 right parenthesis end exponent times c to the power of 10 minus 6 end exponent close parentheses end cell row blank equals cell open parentheses a to the power of negative 14 end exponent times b to the power of 12 times c to the power of 4 close parentheses end cell row blank equals cell open parentheses fraction numerator b to the power of 12 times c to the power of 4 over denominator a to the power of 14 end fraction close parentheses end cell end table


Oleh karena itu, jawaban yang benar adalah C.

0

Roboguru

Bentuk sederhana dari  adalah ...

Pembahasan Soal:

Bentuk sederhana dari 5 to the power of negative 2 end exponent space colon space 5 to the power of negative 4 end exponent cross times 5 to the power of negative 3 end exponent:

table attributes columnalign right center left columnspacing 0px end attributes row cell 5 to the power of negative 2 end exponent space colon space 5 to the power of negative 4 end exponent cross times 5 to the power of negative 3 end exponent end cell equals cell 5 to the power of open parentheses negative 2 close parentheses minus open parentheses negative 4 close parentheses plus open parentheses negative 3 close parentheses end exponent end cell row blank equals cell 5 to the power of negative 1 end exponent end cell end table

Sehingga, bentuk sederhana dari 5 to the power of negative 2 end exponent space colon space 5 to the power of negative 4 end exponent cross times 5 to the power of negative 3 end exponent adalah 5 to the power of negative 1 end exponent.

Jadi, jawaban yang tepat adalah B.

0

Roboguru

Pembahasan Soal:

Sesuai dengan sifat bilangan berpangkat, maka soal di atas dapat diselesaikan sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row cell 21 cubed over 9 squared divided by open parentheses 7 over 2 close parentheses squared end cell equals cell open parentheses 7 times 3 close parentheses cubed over open parentheses 3 squared close parentheses squared divided by 7 squared over 2 squared end cell row blank equals cell fraction numerator 7 cubed times 3 cubed over denominator 3 to the power of 4 end fraction cross times 2 squared over 7 squared end cell row blank equals cell 7 to the power of open parentheses 3 minus 2 close parentheses end exponent 3 to the power of open parentheses 3 minus 4 close parentheses end exponent 2 squared end cell row blank equals cell 7 to the power of 1 3 to the power of negative 1 end exponent 4 end cell row blank equals cell 28 over 3 end cell end table 

Jadi, 21 cubed over 9 squared divided by open parentheses 7 over 2 close parentheses squared equals 28 over 3.

0

Roboguru

Bentuk sederhana dari  adalah ....

Pembahasan Soal:

Akan dicari bentuk sederhana dari open parentheses fraction numerator 9 a to the power of negative 3 end exponent b to the power of negative 5 end exponent over denominator 3 b squared a to the power of 6 end fraction close parentheses squared sebagai berikut

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 9 a to the power of negative 3 end exponent b to the power of negative 5 end exponent over denominator 3 b squared a to the power of 6 end fraction close parentheses squared end cell equals cell open parentheses 3 a to the power of negative 3 minus 6 end exponent b to the power of negative 5 minus 2 end exponent close parentheses squared end cell row blank equals cell open parentheses 3 a to the power of negative 9 end exponent b to the power of negative 7 end exponent close parentheses squared end cell row blank equals cell 3 to the power of 1 cross times 2 end exponent a to the power of negative 9 cross times 2 end exponent b to the power of negative 7 cross times 2 end exponent end cell row blank equals cell 3 squared a to the power of negative 18 end exponent b to the power of negative 14 end exponent end cell row blank equals cell fraction numerator 9 over denominator a to the power of 18 b to the power of 14 end fraction end cell end table

Jadi, jawaban yang tepat adalah E.space  

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Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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