Pertanyaan

J ika f ( n ) = 2 n + 2 6 n − 4 d an g ( n ) = 1 2 n − 1 , n a d a l ah bi l an g an a s l i , maka g ( n ) f ( n ) ​ a d a l ah ....

  1. 1 over 32

  2. 1 over 27

  3. 1 over 18

  4. 1 over 9

  5. 2 over 9

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D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

f left parenthesis x right parenthesis space equals space 2 to the power of n plus 2 end exponent 6 to the power of n minus 4 end exponent space d a n space g left parenthesis n right parenthesis equals 12 to the power of n minus 1 end exponent  fraction numerator f left parenthesis n right parenthesis over denominator g left parenthesis n right parenthesis end fraction equals fraction numerator 2 to the power of n plus 2 end exponent 6 to the power of n minus 4 end exponent over denominator 12 to the power of n minus 1 end exponent end fraction  space space space space space space space space space equals fraction numerator 2 to the power of n.2 squared.12.6 to the power of n over denominator 6 to the power of 4.12 to the power of n end fraction  space space space space space space space space space equals fraction numerator left parenthesis 2.6 right parenthesis to the power of n.2 squared.12 over denominator 2 to the power of 4.3 to the power of 4.12 to the power of n end fraction  space space space space space space space space space equals fraction numerator 12 to the power of n.2 squared.2 squared.3 over denominator 2 to the power of 4.3 to the power of 4.12 to the power of n end fraction  space space space space space space space space space equals fraction numerator 2 to the power of 4.3 over denominator 2 to the power of 4.3 to the power of 4 end fraction  space space space space space space space space space equals 1 over 3 cubed  space space space space space space space space space equals 1 over 27

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Pertanyaan serupa

Bentuk sederhana dari ( 32 p 2 q − 1 r 6 4 p − 1 q 2 r 3 ​ ) − 1 adalah....

13

4.3

Jawaban terverifikasi

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