Iklan

Iklan

Pertanyaan

∫ ( x 5 + 3 x 2 + 1 ) d x = ....

 

Iklan

W. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

.

 integral space open parentheses x to the power of 5 plus 3 x squared plus 1 close parentheses space straight d x equals 1 over 6 x to the power of 6 plus x cubed plus x plus C.

Iklan

Pembahasan

Ingat kembali: Maka: Jadi, .

Ingat kembali:

integral space a space straight d x equals a x plus C integral space open parentheses a x to the power of n close parentheses space straight d x equals fraction numerator a over denominator n plus 1 end fraction x to the power of n plus 1 end exponent plus C 

Maka:

integral space open parentheses x to the power of 5 plus 3 x squared plus 1 close parentheses space straight d x equals 1 over 6 x to the power of 6 plus x cubed plus x plus C 

Jadi, integral space open parentheses x to the power of 5 plus 3 x squared plus 1 close parentheses space straight d x equals 1 over 6 x to the power of 6 plus x cubed plus x plus C.

Latihan Bab

Pengenalan Integral

Integral Tak Tentu

Integral Substitusi

Aplikasi Integral Tak Tentu

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

426

Iklan

Iklan

Pertanyaan serupa

Jika f ( x ) = ∫ ( x 2 + 2 x − 1 ) d x dan f ( 1 ) = 0 , maka rumus fungsi f ( x ) adalah ....

2rb+

3.3

Jawaban terverifikasi

Iklan

Iklan

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2023 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia