Pertanyaan

sin 5 5 ∘ tan 8 5 ∘ − tan 3 0 ∘ = ...

$\frac{tan 8 5 ^{\circ} - tan 3 0 ^{\circ}}{sin 5 5 ^{\circ}} = ...$

O. Rahmawati

Master Teacher

Mahasiswa/Alumni UIN Sunan Gunung Djati Bandung

Jawaban terverifikasi

Pembahasan

Menentukan dengan sifat rumus selisih tangen: Pembahasan: Oleh karena itu, jawaban yang benar adalah B.

Menentukan dengan sifat rumus selisih tangen:

$tan space A minus space B equals fraction numerator sin space open parentheses A minus B close parentheses over denominator cos space A space cos space B end fraction$

Pembahasan:

$table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator tan space 85 degree minus tan space 30 degree over denominator sin space 55 degree end fraction end cell equals cell fraction numerator begin display style fraction numerator sin open parentheses 85 degree minus 30 degree close parentheses over denominator cos space 85 degree space cos space 30 degree end fraction end style over denominator sin space 55 degree end fraction end cell row blank equals cell fraction numerator begin display style fraction numerator sin space 55 degree over denominator cos space 85 degree space cos space 30 degree end fraction end style over denominator sin space 55 degree end fraction end cell row blank equals cell fraction numerator up diagonal strike sin space 55 degree end strike over denominator cos space 85 degree space cos space 30 degree end fraction cross times fraction numerator 1 over denominator up diagonal strike sin space 55 degree end strike end fraction end cell row blank equals cell fraction numerator 1 over denominator cos space 85 degree space cos space 30 degree end fraction end cell row blank equals cell fraction numerator 1 over denominator cos space 85 degree space open parentheses begin display style 1 half square root of 3 end style close parentheses end fraction end cell row blank equals cell fraction numerator 2 over denominator square root of 3 space cos space 85 degree end fraction space end cell row blank equals cell fraction numerator 2 cross times square root of 3 over denominator square root of 3 cross times square root of 3 end fraction open parentheses cosec space 85 degree close parentheses end cell row blank equals cell fraction numerator 2 square root of 3 over denominator 3 end fraction open parentheses cosec space 85 degree close parentheses end cell end table$

Oleh karena itu, jawaban yang benar adalah B.