Pertanyaan

( sin 3 0 ∘ ) 2 + ( cos 3 0 ∘ ) 2 2 ( cos 6 0 ∘ ) 2 + 4 ( sec 3 0 ∘ ) 2 − ( tan 4 5 ∘ ) 2

$\frac{2 ( cos 6 0 ^{\circ} ) ^{2} + 4 ( sec 3 0 ^{\circ} ) ^{2} - ( tan 4 5 ^{\circ} ) ^{2}}{( sin 3 0 ^{\circ} ) ^{2} + ( cos 3 0 ^{\circ} ) ^{2}}$

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

Dengan demikian,

$begin mathsize 14px style fraction numerator 2 left parenthesis cos space 60 degree right parenthesis squared plus 4 left parenthesis sec space 30 degree right parenthesis to the power of 2 end exponent minus left parenthesis tan space 45 degree right parenthesis squared over denominator left parenthesis sin space 30 degree right parenthesis squared plus left parenthesis cos space 30 degree right parenthesis squared end fraction equals fraction numerator 2 open parentheses cos blank 60 degree close parentheses squared plus 4 open parentheses fraction numerator 1 over denominator cos space 30 degree end fraction close parentheses squared minus open parentheses tan blank 45 degree close parentheses squared over denominator open parentheses sin blank 30 degree close parentheses squared plus open parentheses cos blank 30 degree close parentheses squared end fraction equals fraction numerator 2 open parentheses 1 half close parentheses squared plus 4 open parentheses fraction numerator 2 square root of 3 over denominator 3 end fraction close parentheses squared minus open parentheses 1 close parentheses squared over denominator open parentheses 1 half close parentheses squared plus open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses squared end fraction equals fraction numerator 2 open parentheses 1 fourth close parentheses plus 4 open parentheses 12 over 9 close parentheses minus 1 over denominator 1 fourth plus 3 over 4 end fraction equals fraction numerator open parentheses 1 half close parentheses plus 4 open parentheses 4 over 3 close parentheses minus 1 over denominator 4 over 4 end fraction equals fraction numerator 1 half plus 16 over 3 minus 1 over denominator 1 end fraction equals 3 over 6 plus 32 over 6 minus 6 over 6 equals 29 over 6 equals 4 5 over 6 end style$

Dengan demikian,