Pertanyaan

aka r − aka r p ers amaan x 2 + ( a − 1 ) x + 2 = 0 a d a l ah α d an β . J ika α = 2 β d an a > 0 , maka ni l ai a = ...

$aka r - aka r p ers amaan x^{2} + (a - 1) x + 2 = 0 a d a l ah α d an β . J ika α = 2 β d an a > 0, maka ni l ai a = ...$

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N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

$rightwards double arrow alpha space. space beta space equals fraction numerator space c over denominator a end fraction space comma space s u b s t i t u s i space alpha space equals space 2 beta space s e h i n g g a space d i p e r o l e h space colon space space space space space space space space 2 beta space. space beta space equals space 2 over 1 space space space space space space space 2 beta squared space equals space 1 space space space space space space space space beta equals space plus-or-minus 1 space space space space space space space j i k a space beta space equals space 1 space m a k a space alpha space equals space 2 space space space space space space space j i k a space beta space equals space minus 1 space m a k a space alpha space equals space minus 2 space rightwards double arrow alpha space plus space beta space equals space minus space b over a space space space space space space alpha space plus space beta space equals space minus space fraction numerator a minus 1 over denominator 1 end fraction space a g a r space a space b e r n i l a i space p o s i t i f space n i l a i space y a n g space m e m e n u h i space a d a l a h space j i k a space alpha space equals space minus 2 space d a n space beta space equals space minus 1 space minus 2 space plus space left parenthesis negative 1 right parenthesis equals space minus space left parenthesis a minus 1 right parenthesis space minus 3 equals space minus a space plus space 1 space a equals space 1 space plus 3 space a equals space 4$

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