∫(3x−2)2dx = ...

Pertanyaan

begin mathsize 14px style integral open parentheses 3 x minus 2 close parentheses squared text dx end text end style = ...

  1. begin mathsize 14px style 3 x cubed plus 6 x squared plus 4 x plus text C end text end style

  2. begin mathsize 14px style 3 x cubed minus 6 x squared minus 4 x plus text C end text end style

  3. begin mathsize 14px style 3 x cubed minus 6 x squared plus 4 x plus text C end text end style

  4. begin mathsize 14px style 3 x squared minus 12 x squared plus 4 x plus text C end text end style

  5. begin mathsize 14px style 3 x squared plus 12 x squared plus 4 x plus text C end text end style

N. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Padang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

Pembahasan

Perhatikan perhitungan berikut ini.

Ingat:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral left parenthesis f open parentheses x close parentheses plus-or-minus g open parentheses x close parentheses right parenthesis text d end text x end cell equals cell integral f left parenthesis x right parenthesis text d end text x plus-or-minus integral g left parenthesis x right parenthesis text d end text x end cell row cell integral a d x end cell equals cell a x plus text C end text end cell row cell integral x to the power of n d x end cell equals cell fraction numerator 1 over denominator n plus 1 end fraction x to the power of n plus 1 end exponent plus text C end text end cell end table end style

maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral open parentheses 3 x minus 2 close parentheses squared d x end cell equals cell integral open parentheses 9 x squared minus 12 x plus 4 close parentheses d x end cell row blank equals cell integral 9 x squared d x minus integral 12 x d x plus integral 4 d x end cell row blank equals cell fraction numerator 9 over denominator 2 plus 1 end fraction x to the power of 2 plus 1 end exponent minus fraction numerator 12 over denominator 1 plus 1 end fraction x to the power of 1 plus 1 end exponent plus 4 x plus text C end text end cell row blank equals cell 9 over 3 x cubed minus 12 over 2 x squared plus 4 x plus text C end text end cell row blank equals cell 3 x cubed minus 6 x squared plus 4 x plus text C end text end cell end table end style

Jadi, hasilbegin mathsize 14px style integral open parentheses 3 x minus 2 close parentheses squared text dx end text end style adalah Error converting from MathML to accessible text..

Dengan demikian, jawaban yang tepat adalah C.

84

0.0 (0 rating)

Pertanyaan serupa

Jika f (x)=4x3+6x−7, f(1)=3 maka f(2)=....

46

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia