Iklan

Iklan

Pertanyaan

CH 3 ​ COOK ( M r ​ = 98) yang terdapat dalam100 mL larutan CH 3 ​ COOK dengan pH = 9 adalah ... gram. ( K a ​ CH 3 ​ COOH = 1 0 − 5 )

( = 98) yang terdapat dalam 100 mL larutan dengan pH = 9 adalah ... gram.

  1. 0,245

  2. 0,49

  3. 0,98

  4. 9,8

  5. 19,6

Iklan

Q. 'Ainillana

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

Jawaban terverifikasi

Iklan

Pembahasan

CH 3 ​ COOK yang terdapat dalam100 mL larutan CH 3 ​ COOK dengan pH = 9 adalah 0,98 gram. Pilihan jawaban C. Garam CH 3 ​ COOK merupakan garam yang berasal dari asam lemah ( CH 3 ​ COO − ) dan basa kuat KOH, yang bersifat basa. Sehingga untuk mencari massanya kita dapat menggunakan rumus hidrolisis garam basa. Mencari konsentrasi OH − Mencari molaritas larutan (M) Mencari massa garam CH 3 ​ COOK M = Mr Massa ( gr ) ​ x Volume ( ml ) 1000 ​ 0 , 1 = 98 Massa ( gr ) ​ x 100 1000 ​ 0 , 1 x 98 = Massa x 10 10 9 , 8 ​ = Massa 0 , 98 = Massa Massa CH 3 ​ COOK = 0 , 98 gram .

 yang terdapat dalam 100 mL larutan dengan pH = 9 adalah 0,98 gram. Pilihan jawaban C.

Garam  merupakan garam yang berasal dari asam lemah  dan basa kuat KOH, yang bersifat basa. Sehingga untuk mencari massanya kita dapat menggunakan rumus hidrolisis garam basa.

Mencari konsentrasi 

pH space space space space equals space 9 pOH space equals space 14 minus sign 9 space equals space 5 pOH space equals space minus sign log space open square brackets O H to the power of minus sign close square brackets space space 5 space space space space equals minus sign log space open square brackets O H to the power of minus sign close square brackets minus sign log space 10 to the power of negative sign 5 end exponent space equals minus sign log space open square brackets O H to the power of minus sign close square brackets space bold open square brackets O H to the power of bold minus sign bold close square brackets bold space bold space bold space bold space bold space bold space bold space bold space bold equals bold space bold 10 to the power of bold minus sign bold 5 end exponent

 

Mencari molaritas larutan (M)

open square brackets O H to the power of minus sign close square brackets space equals space square root of Kw over Ka x space open square brackets C H subscript 3 C O O to the power of minus sign close square brackets end root 10 to the power of negative sign 5 end exponent space space space equals space square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent x space open square brackets C H subscript 3 C O O to the power of minus sign close square brackets end root left parenthesis 10 to the power of negative sign 5 end exponent right parenthesis squared equals space 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent x space open square brackets C H subscript 3 C O O to the power of minus sign close square brackets 10 to the power of negative sign 10 end exponent space space equals space 10 to the power of negative sign 9 end exponent space x space open square brackets C H subscript 3 C O O to the power of minus sign close square brackets open square brackets C H subscript 3 C O O to the power of minus sign close square brackets space equals space 10 to the power of negative sign 10 end exponent over 10 to the power of negative sign 9 end exponent open square brackets C H subscript 3 C O O to the power of minus sign close square brackets space equals 10 to the power of negative sign 1 end exponent bold open square brackets C H subscript bold 3 C O O to the power of bold minus sign bold close square brackets bold space bold equals bold 0 bold comma bold 1 bold space italic M  C H subscript 3 C O O K space rightwards arrow space C H subscript 3 C O O to the power of minus sign space plus space K to the power of plus sign bold space bold space bold space bold space bold space bold space bold space bold 0 bold comma bold 1 bold space italic M bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space 0 comma 1 space M  italic M bold space C H subscript bold 3 C O O K bold space bold equals bold space bold 0 bold comma bold 1 bold space italic M

 

Mencari massa garam 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

114

Iklan

Iklan

Pertanyaan serupa

Jika K a ​ ( CH 3 ​ COOH ) = 1 × 1 0 − 5 maka pH larutan CH 3 ​ COONa 0,1 M adalah ….

7

4.7

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia