Nurzilahaniyah N
02 November 2024 00:34
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Nurzilahaniyah N
02 November 2024 00:34
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Sumber W

Community
02 November 2024 02:24
ok saya bantu jawab ya....
1. <AOB = 120° dan <BOC = 75°
Busur BC = 50 cm
<BOC/<AOC = Busur BC/Busur AC
75°/120° = 50/Busur AC
5/8 = 50/Busur AC
Busur AC = (8 x 50)/5
= 80 cm
2. L.AOB = 63 cm3
<AOB = 105° dan <DOC = 75°
<DOC/<AOB = L.DOC/L.AOB
75°/105° =L.DOC/63
5/7 = L.DOC/63
L.DOC = (63 x 5)/7
= 45 cm2
3. <ABD = 65°
<BAC = <ABD = 65° (karena segitiga AOB adalah segitiga samakaki
dimana AO = BO)
<AOB = 180° - (<BAC + <ABD)
= 180° - (65° + 65°)
= 180° - 130°
= 50°
<BOC = 180° - <AOB
= 180° - 50°
= 130°
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