Nailah A

23 Februari 2025 07:38

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Nailah A

23 Februari 2025 07:38

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M F

23 Februari 2025 14:39

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<p>dik:</p><ul><li>n(s)=100</li><li>n(v)=60</li><li>n(y)=70</li><li>n(v∩y)=40</li></ul><p>dit: p(v<sup>c</sup>)=..?</p><p>jwb: &nbsp;</p><ul><li>&nbsp;n(s)=n(v)+n(y)-n(v∩y)+n(v∪y<sup>c</sup>) &nbsp; &nbsp; &nbsp;&nbsp;</li></ul><p>&nbsp; &nbsp; &nbsp; &nbsp;100= &nbsp;60 + 70 - 40 + n(v∪y<sup>c</sup>)&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp;100= 130 - 40 + n(v∪y<sup>c</sup>)&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp;100= 90 + n(v∪y<sup>c</sup>)&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; 10 = n(v∪y<sup>c</sup>)</p><ul><li>n(v<sup>c</sup>)=(n(v)-n(v∩y)) + n(v∪y<sup>c</sup>) &nbsp;</li></ul><p>&nbsp; &nbsp; &nbsp; n(v<sup>c</sup>)=( 60 - 40 ) + 10</p><p>&nbsp; &nbsp; &nbsp; n(v<sup>c</sup>)= 20 + 10</p><p>&nbsp; &nbsp; &nbsp; n(v<sup>c</sup>)= 30</p><ul><li><i>P</i>(v<sup>c</sup>)= n(v<sup>c</sup>)/n(s)</li></ul><p>&nbsp; &nbsp; &nbsp;&nbsp;<i>P</i>(v<sup>c</sup>)= 30/100<sup>2</sup></p><p><sup>&nbsp; &nbsp; &nbsp; &nbsp;&nbsp;</sup><i>P</i>(v<sup>c</sup>)= 3/1000</p>

dik:

  • n(s)=100
  • n(v)=60
  • n(y)=70
  • n(v∩y)=40

dit: p(vc)=..?

jwb:  

  •  n(s)=n(v)+n(y)-n(v∩y)+n(v∪yc)       

       100=  60 + 70 - 40 + n(v∪yc

       100= 130 - 40 + n(v∪yc

       100= 90 + n(v∪yc

        10 = n(v∪yc)

  • n(vc)=(n(v)-n(v∩y)) + n(v∪yc)  

      n(vc)=( 60 - 40 ) + 10

      n(vc)= 20 + 10

      n(vc)= 30

  • P(vc)= n(vc)/n(s)

      P(vc)= 30/1002

        P(vc)= 3/1000


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