Xy S
30 September 2025 04:07
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Xy S
30 September 2025 04:07
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Latihan !! ①Tentukan akar - akar Persamaan kuadrat X² - g = 0 2 Tentukan akar Persamaan Kuadrat dengan Kuadrat Sempurna. 9. X²+ yx - 2 = 0 b X² + 8y- g = 0 ③ Tentukan akar-akar persamaan Huadrat dengan ABC a 2x² + 4x + 1 = 0 b. 2x²- 3x - 9 = 0
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Fadhil I
30 September 2025 06:13
<p>1)</p><p>x² - g = 0</p><p>x² = g</p><p>x = ± √g</p><p> </p><p>• x1 = √g</p><p>• x2 = -√g</p><p> </p><p>2)</p><p>a)</p><p>x² + yx - 2 = 0</p><p>(x + y/2)² - y²/4 - 2 = 0</p><p>(x + y/2)² = y²/4 + 2</p><p>x + y/2 = ± √(y²/4 +2)</p><p>x = -y/2 ± √(y²/4 + 2)</p><p> </p><p>• x1 = -y/2 + √(y²/4 +2)</p><p>• x2 = -y/2 - √(y²/4 - 2)</p><p> </p><p>b)</p><p>x² - 8x - g = 0</p><p>(x - 4)² - 16 - g = 0</p><p>(x - 4)² = 16 + g</p><p>x - 4 = ±√(16 + g)</p><p>x = 4 ± √(16 + g)</p><p> </p><p>• x1 = 4 + √(16 + g)</p><p>• x2 = 4 - √(16 - g)</p><p> </p><p>3) Rumus ABC </p><p>x = {- b ± √(b² - 4ac)} / (2a)</p><p>a) </p><p>2x² + 4x + 1 = 0</p><p>x = {-4 ± √(4² - 4×2×1)} / (2 × 2)</p><p>x = {-4 ± √(16 - 8)} / 4</p><p>x = (-4 ± √12) / 4</p><p>x = {-4 ± √(4×3)} / 4</p><p>x = (-4 ± √4√3) / 4</p><p>x = (-4 ± 2√3) / 4</p><p>x = (-2 ± √3) / 2</p><p> </p><p>• x1 = (-2 + √3) / 2 = -1 + ½√3</p><p>• x2 = (-2 - √ 3) / 2 = -1 - ½√3</p><p> </p><p>b) </p><p>2x² - 3x - 9 = 0</p><p>x = [-(-3) ± √{3² - 4×2×(-9)}] / (2×2)</p><p>x = {3 ± √(9 + 72)} / 4</p><p>x = (3 ± √81) / 4</p><p>x = (3 ± 9) / 4</p><p> </p><p>• x1 = (3+9) / 4 = 12 / 4 = 3</p><p>• x2 = (3 -9) / 4 = -6/4 = -3/2</p>
1)
x² - g = 0
x² = g
x = ± √g
• x1 = √g
• x2 = -√g
2)
a)
x² + yx - 2 = 0
(x + y/2)² - y²/4 - 2 = 0
(x + y/2)² = y²/4 + 2
x + y/2 = ± √(y²/4 +2)
x = -y/2 ± √(y²/4 + 2)
• x1 = -y/2 + √(y²/4 +2)
• x2 = -y/2 - √(y²/4 - 2)
b)
x² - 8x - g = 0
(x - 4)² - 16 - g = 0
(x - 4)² = 16 + g
x - 4 = ±√(16 + g)
x = 4 ± √(16 + g)
• x1 = 4 + √(16 + g)
• x2 = 4 - √(16 - g)
3) Rumus ABC
x = {- b ± √(b² - 4ac)} / (2a)
a)
2x² + 4x + 1 = 0
x = {-4 ± √(4² - 4×2×1)} / (2 × 2)
x = {-4 ± √(16 - 8)} / 4
x = (-4 ± √12) / 4
x = {-4 ± √(4×3)} / 4
x = (-4 ± √4√3) / 4
x = (-4 ± 2√3) / 4
x = (-2 ± √3) / 2
• x1 = (-2 + √3) / 2 = -1 + ½√3
• x2 = (-2 - √ 3) / 2 = -1 - ½√3
b)
2x² - 3x - 9 = 0
x = [-(-3) ± √{3² - 4×2×(-9)}] / (2×2)
x = {3 ± √(9 + 72)} / 4
x = (3 ± √81) / 4
x = (3 ± 9) / 4
• x1 = (3+9) / 4 = 12 / 4 = 3
• x2 = (3 -9) / 4 = -6/4 = -3/2
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