Jika AB dan AC panjangnya sama, tentukan nilai p

<p>Diketahui:</p><p>Sudut B = 180⁰ – 108⁰&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 72⁰</p><p>Sudut dalam A berseberangan dengan 2P⁰</p><p>Sudut A = 2P⁰</p><p>Sudut C = 4P⁰</p><p>Ditanya:&nbsp;</p><p>P = ....?</p><p>&nbsp;</p><p>Total sudut segitiga = 180⁰&nbsp;</p><p>Total ∠ABC = 180⁰</p><p>2P⁰+72⁰+4P⁰= 180⁰</p><p>&nbsp; &nbsp; &nbsp; 6P⁰ + 72⁰ = 180⁰</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;6P⁰ = 180⁰–72⁰</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;6P⁰ = 108⁰</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;P⁰ = 108⁰ ÷ 6</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;P⁰ = 18⁰</p>