gambar grafis fungsi dari F(x) = x² -1

<p>Mari kita bahas....</p><p>f(x) &nbsp;= x² - 1</p><p>a = 1, b = 0 dan c = -1</p><p>&nbsp;</p><p>Menenentukan sumbu simetri (x_p) dan titik balik&nbsp;</p><p>x_p = -b/a</p><p>&nbsp; &nbsp; &nbsp; &nbsp;= -0/1</p><p>&nbsp; &nbsp; &nbsp; &nbsp;= 0</p><p>y_p = (b² - 4ac)/-4a</p><p>&nbsp; &nbsp; &nbsp; = (0² - 4(1)(-1))/-4(1)</p><p>&nbsp; &nbsp; &nbsp; = 4/-4</p><p>&nbsp; &nbsp; &nbsp; &nbsp;= -1</p><p>Koordinat titik balik adalah (0,-1)</p><p>&nbsp;</p><p>Kita cari titik-titik yang lain</p><p>x &nbsp; | &nbsp; y &nbsp; | &nbsp;(x,y)</p><p>------------------</p><p>2 &nbsp;| &nbsp; 3 &nbsp; | (2,3)</p><p>1 &nbsp;| &nbsp; 0 &nbsp; | (1,0)</p><p>0 &nbsp;| &nbsp; -1 &nbsp;| (0,-1)</p><p>-1 | &nbsp;0 &nbsp; &nbsp;| &nbsp;(1,0)</p><p>-2 | &nbsp; 3 &nbsp; | &nbsp;(-2,3)</p><p>&nbsp;</p><p>Garfiknya seperti dibawah :</p>