bantu jawab

<p>Untuk menyelesaikan reaksi tersebut kita perlu mengetahui mol dari salah satu reaktannya</p><ul><li>Ca3(PO4)2</li></ul><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Mr = 3(40) + 2(31 + 4(16)) = 310</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; n = Massa/Mr = 300/310 =0,967 mol</p><p>Lalu hitung mol produk menggunakan perbandingan koefisien&nbsp;</p><ul><li>Ca(H2PO4)2</li></ul><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 1 × 0,967 mol Ca3(PO4)2 = 0,967 mol</p><ul><li>CaSO4</li></ul><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2 × 0,967 mol Ca3(PO4)2 =1,934 mol</p><p>Kemudian kita menghitung massa dari masing masing produk</p><ul><li>&nbsp;Ca(H2PO4)2</li></ul><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Mr = 40 + 2(2(1) + 31 + 4(16) = 234</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Massa = n × Mr = 234 × 0,967 = 226, 27 gram</p><ul><li>CaSO4</li></ul><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Mr = 40 + 32 + 4(16) = 136</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Massa = n × Mr = 136 × 1,934 = 263 gram</p><p>Terakhir kita menghitung massa dari pupuk superfosfat</p><p>Massa CaSO4 + Massa Ca(H2PO4)2 = 226,27 gram + 263 gram = 489,27 ≈ 489,7</p><p><strong>Jadi jawabannya yang b.</strong></p><p>&nbsp;</p>