Zat A dapat bereaksi dengan zat B menjadi zat C, menurut persamaan reaksi:   A+2B→C Berdasarkan data percobaan di atas, persamaan laju reaksinya adalah ...

Pertanyaan

Zat A dapat bereaksi dengan zat B menjadi zat C, menurut persamaan reaksi:
 

A and 2 B yields C

Berdasarkan data percobaan di atas, persamaan laju reaksinya adalah ...space

  1. v double bond k open square brackets A close square brackets open square brackets B close square brackets to the power of begin inline style bevelled 1 half end style end exponent

  2. v double bond k open square brackets A close square brackets open square brackets B close square brackets

  3. v double bond k open square brackets A close square brackets open square brackets B close square brackets to the power of begin inline style 2 end style end exponent

  4. v double bond k open square brackets A close square brackets squared open square brackets B close square brackets

  5. v double bond k open square brackets A close square brackets squared open square brackets B close square brackets squared

B. Rohmawati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Pembahasan

Jawaban yang benar adalah opsi D.

Untuk reaksi A and 2 B yields C, persamaan laju reaksi v double bond k open square brackets A close square brackets to the power of x open square brackets B close square brackets to the power of y.

  • Digunakan data 1 dan 2

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets fraction numerator 0 comma 02 over denominator 0 comma 01 end fraction close square brackets to the power of x open square brackets fraction numerator 0 comma 4 over denominator 0 comma 1 end fraction close square brackets to the power of y end cell equals cell fraction numerator 1 over 54 over denominator 1 over 864 end fraction end cell row cell 2 to the power of x middle dot 2 to the power of 2 y end exponent end cell equals cell 2 to the power of 4 end cell row cell 2 to the power of x and 2 y end exponent end cell equals cell 2 to the power of 4 end cell row cell x and 2 y end cell equals cell 4 space............. left parenthesis persamaan space 1 right parenthesis end cell end table

  • Digunakan data 1 dan 3

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets fraction numerator 0 comma 03 over denominator 0 comma 01 end fraction close square brackets to the power of x open square brackets fraction numerator 0 comma 3 over denominator 0 comma 1 end fraction close square brackets to the power of y end cell equals cell fraction numerator 1 over 32 over denominator 1 over 864 end fraction end cell row cell 3 to the power of x middle dot 3 to the power of y end cell equals cell 3 cubed end cell row cell 3 to the power of x and y end exponent end cell equals 3 row cell x and y end cell equals 3 row x equals cell 3 minus sign y space............. left parenthesis persamaan space 2 right parenthesis end cell end table

  • Substitusikan persamaan 2 ke 1

table attributes columnalign right center left columnspacing 0px end attributes row cell left parenthesis 3 minus sign y right parenthesis plus 2 y end cell equals 4 row cell 3 plus y end cell equals 4 row y equals cell 4 minus sign 3 end cell row y equals 1 end table

  • Masukkan nilai y ke persamaan 2

x equals 3 minus sign y x equals 3 minus sign 1 x equals 2 

Persamaan laju reaksinya adalah v double bond k open square brackets A close square brackets squared open square brackets B close square brackets

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