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Turunan dari fungsi g ( t ) = 2 − sin 3 t 2 + cos 3 t ​ adalah ....

Turunan dari fungsi  adalah ....

  1. begin mathsize 14px style negative tan space 3 straight t end style 

  2. begin mathsize 14px style negative cot space 3 straight t end style 

  3. begin mathsize 14px style fraction numerator 6 space sin space 3 straight t plus 6 space cos space 3 straight t minus 3 over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end style 

  4. begin mathsize 14px style fraction numerator negative 6 space sin space 3 straight t plus 6 space cos space 3 straight t plus 3 over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end style 

  5. begin mathsize 14px style fraction numerator 6 space sin space 3 straight t minus 6 space cos space 3 straight t plus 3 over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end style 

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

jawaban yang tepat adalah D.

Pembahasan

Misal dan ,maka dan Ingat bahwa jika ,maka Perhatikan bahwa , sehingga Jadi, jawaban yang tepat adalah D.

Misal begin mathsize 14px style straight u left parenthesis straight t right parenthesis equals 2 plus cos space 3 straight t end style dan begin mathsize 14px style straight v left parenthesis straight t right parenthesis equals 2 minus sin space 3 straight t end style, maka begin mathsize 14px style straight u to the power of apostrophe left parenthesis straight t right parenthesis equals negative 3 space sin space 3 straight t end style dan begin mathsize 14px style straight v to the power of apostrophe left parenthesis straight t right parenthesis equals negative 3 space cos space 3 straight t end style 

Ingat bahwa jika begin mathsize 14px style straight g left parenthesis straight t right parenthesis equals fraction numerator straight u left parenthesis straight t right parenthesis over denominator straight v left parenthesis straight t right parenthesis end fraction end style, maka

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight g to the power of apostrophe left parenthesis straight t right parenthesis end cell equals cell fraction numerator straight u to the power of apostrophe left parenthesis straight t right parenthesis times straight v left parenthesis straight t right parenthesis minus straight u left parenthesis straight t right parenthesis times straight v to the power of apostrophe left parenthesis straight t right parenthesis over denominator left parenthesis straight v left parenthesis straight t right parenthesis right parenthesis squared end fraction end cell row blank equals cell fraction numerator left parenthesis negative 3 space sin space 3 straight t right parenthesis times left parenthesis 2 minus sin space 3 straight t right parenthesis minus left parenthesis 2 plus cos space 3 straight t right parenthesis times left parenthesis negative 3 space cos space 3 straight t right parenthesis over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end cell row blank equals cell fraction numerator negative 6 space sin space 3 straight t plus 3 space sin squared space 3 straight t minus left parenthesis negative 6 space cos space 3 straight t minus 3 space cos squared space 3 straight t right parenthesis over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end cell row blank equals cell fraction numerator negative 6 space sin space 3 straight t plus 3 space sin squared space 3 straight t plus 6 space cos space 3 straight t plus 3 space cos squared space 3 straight t over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end cell row blank equals cell fraction numerator negative 6 space sin space 3 straight t plus 6 space cos space 3 straight t plus 3 open parentheses sin squared space 3 straight t plus cos squared space 3 straight t close parentheses over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end cell end table end style 

Perhatikan bahwa Error converting from MathML to accessible text., sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight g to the power of apostrophe left parenthesis straight t right parenthesis end cell equals cell fraction numerator negative 6 space sin space 3 straight t plus 6 space cos space 3 straight t plus 3 open parentheses sin squared space 3 straight t plus cos squared space 3 straight t close parentheses over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end cell row blank equals cell fraction numerator negative 6 space sin space 3 straight t plus 6 space cos space 3 straight t plus 3 over denominator left parenthesis 2 minus sin space 3 straight t right parenthesis squared end fraction end cell end table end style 

Jadi, jawaban yang tepat adalah D.

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