Roboguru
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Tiga buah vektor  F1​​=(−15 i + 10 j​ ) satuan,  F2​​=(10 i + 5 j​ ) satuan, dan  F3​​=(5 i − 4 j​ ) satuan. Tentukan : a.   F1​​ + F2​​ − F3​​  b.   F1​​ − F2​​ − F3​​

Pertanyaan

Tiga buah vektor  begin mathsize 14px style stack F subscript 1 with rightwards arrow on top equals left parenthesis negative 15 space i with hat on top space plus space 10 space j with hat on top space right parenthesis end style satuan,  begin mathsize 14px style stack F subscript 2 with rightwards arrow on top equals left parenthesis 10 space i with hat on top space plus space 5 space j with hat on top space right parenthesis end style satuan, dan  begin mathsize 14px style stack F subscript 3 with rightwards arrow on top equals left parenthesis 5 space i with hat on top space minus space 4 space j with hat on top space right parenthesis end style satuan. Tentukan :
a.   begin mathsize 14px style stack F subscript 1 with rightwards arrow on top space plus space stack F subscript 2 with rightwards arrow on top space minus space stack F subscript 3 with rightwards arrow on top end style 

b.   begin mathsize 14px style stack F subscript 1 with rightwards arrow on top space minus space stack F subscript 2 with rightwards arrow on top space minus space stack F subscript 3 with rightwards arrow on top end style 

  1. ... 

  2. ... 

N. Puspita

Master Teacher

Jawaban terverifikasi

Pembahasan

Diketahui :

undefined 

stack size 14px F subscript size 14px 2 with size 14px rightwards arrow on top size 14px equals size 14px left parenthesis size 14px 10 size 14px space size 14px i with size 14px hat on top size 14px space size 14px plus size 14px space size 14px 5 size 14px space size 14px j with size 14px hat on top size 14px space size 14px right parenthesis 

stack size 14px F subscript size 14px 3 with size 14px rightwards arrow on top size 14px equals size 14px left parenthesis size 14px 5 size 14px space size 14px i with size 14px hat on top size 14px space size 14px minus size 14px space size 14px 4 size 14px space size 14px j with size 14px hat on top size 14px space size 14px right parenthesis 

Ditanyakan :
a. stack F subscript 1 with rightwards arrow on top space plus space stack F subscript 2 with rightwards arrow on top space minus space stack F subscript 3 with rightwards arrow on top 
b. stack F subscript 1 with rightwards arrow on top space minus space stack F subscript 2 with rightwards arrow on top space minus space stack F subscript 3 with rightwards arrow on top  . 

Pembahasan :

begin mathsize 14px style stack F subscript 1 with rightwards arrow on top space plus space stack F subscript 2 with rightwards arrow on top space minus space stack F subscript 3 with rightwards arrow on top equals left parenthesis negative 15 space i with hat on top plus 10 space j with hat on top right parenthesis space plus space left parenthesis 10 space i with hat on top plus 5 space j with hat on top right parenthesis space minus space left parenthesis 5 space i with hat on top minus 4 space j with hat on top right parenthesis equals left parenthesis negative 10 space i with hat on top plus 19 space j with hat on top right parenthesis space end style  

 

b.

begin mathsize 14px style stack F subscript 1 with rightwards arrow on top space minus space stack F subscript 2 with rightwards arrow on top space minus space stack F subscript 3 with rightwards arrow on top equals left parenthesis negative 15 space i with hat on top space plus space 10 space j with hat on top right parenthesis space minus left parenthesis 10 space i with hat on top space plus space 5 space j with hat on top right parenthesis space minus space left parenthesis 5 space i with hat on top space minus space 4 space j with hat on top right parenthesis equals left parenthesis negative 30 space i with hat on top space plus space 9 space j with hat on top right parenthesis end style 

Jadi stack bold F subscript bold 1 with bold rightwards arrow on top bold space bold plus bold space stack bold F subscript bold 2 with bold rightwards arrow on top bold space bold minus bold space stack bold F subscript bold 3 with bold rightwards arrow on top bold space bold equals bold space bold left parenthesis bold minus bold 10 bold space bold i with bold hat on top bold plus bold 19 bold space bold j with bold hat on top bold right parenthesis bold space dan  stack bold F subscript bold 1 with bold rightwards arrow on top bold space bold minus bold space stack bold F subscript bold 2 with bold rightwards arrow on top bold space bold minus bold space stack bold F subscript bold 3 with bold rightwards arrow on top bold space bold equals bold space bold left parenthesis bold minus bold 30 bold space bold i with bold hat on top bold space bold plus bold space bold 9 bold space bold j with bold hat on top bold right parenthesis 

 

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Pertanyaan serupa

Perhatikan tiga vektor berikut!   Nilai resultan ketiga vektor tersebut adalah....

1rb+

0.0

Jawaban terverifikasi

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