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Tentukan nilai p yang memenuhi hubungan k = 0 ∑ 4 ​ ( 2 + 3 k ) k = 0 ∑ 3 ​ 2 p 2 ​ = 5 .

Tentukan nilai p yang memenuhi hubungan .

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S. Yoga

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

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nilai adalah atau .

nilai begin mathsize 14px style p end style adalah begin mathsize 14px style – 5 end style atau undefined.

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Dengan demikian, diperoleh: Jadi, nilai adalah atau .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell sum from k equals 0 to 4 of left parenthesis 2 plus 3 k right parenthesis end cell equals cell sum from k equals 0 to 4 of 2 plus sum from k equals 0 to 4 of 3 k end cell row blank equals cell 10 plus 3 sum from k equals 0 to 4 of k end cell row blank equals cell 10 plus 3 left parenthesis 0 plus 1 plus 2 plus 3 plus 4 right parenthesis end cell row blank equals cell 10 plus 3 left parenthesis 10 right parenthesis end cell row blank equals 40 end table end style 

Dengan demikian, diperoleh:

begin mathsize 14px style fraction numerator begin display style sum from k equals 0 to 3 of 2 p squared end style over denominator begin display style sum from k equals 0 to 4 of left parenthesis 2 plus 3 k right parenthesis end style end fraction equals 5 left right double arrow fraction numerator begin display style left parenthesis 3 minus 0 plus 1 right parenthesis 2 p squared end style over denominator begin display style 40 end style end fraction equals 5 space space space space space space space space space space space space space space space space space space space space space space space space space left right double arrow fraction numerator begin display style 8 p squared end style over denominator begin display style 40 end style end fraction equals 5 space space space space space space space space space space space space space space space space space space space space space space space space space left right double arrow fraction numerator begin display style p squared end style over denominator begin display style 5 end style end fraction equals 5 space space space space space space space space space space space space space space space space space space space space space space space space space left right double arrow p squared equals 25 space space space space space space space space space space space space space space space space space space space space space space space space space left right double arrow p equals plus-or-minus 5 end style 

Jadi, nilai begin mathsize 14px style p end style adalah begin mathsize 14px style – 5 end style atau undefined.

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