Pertanyaan

Tentukan nilai p, q, r dengan persamaan berikut: x 3 − 2 x − x + 2 6 x 2 − 7 x − 1 = x − 2 p + x − 1 q + x + 1 r

Tentukan nilai p, q, r dengan persamaan berikut:

$\frac{6 x ^{2} - 7 x - 1}{x ^{3} - 2 x - x + 2} = \frac{p}{x - 2} + \frac{q}{x - 1} + \frac{r}{x + 1}$

r = 2, q = 1, p = 3
r = 1, q = 2, p = 3
r = 3, q = 2, p = 1
r = 2, q = 2, p = 1
r = 1, q = 1, p = 3

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D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

$equals fraction numerator p left parenthesis x minus 1 right parenthesis left parenthesis x minus 1 right parenthesis plus q left parenthesis x minus 2 right parenthesis left parenthesis x plus 1 right parenthesis plus r left parenthesis x minus 2 right parenthesis left parenthesis x minus space 1 right parenthesis over denominator left parenthesis x minus 2 right parenthesis left parenthesis x minus 1 right parenthesis left parenthesis x plus 1 right parenthesis end fraction equals fraction numerator p left parenthesis x squared minus 1 right parenthesis plus q left parenthesis x squared minus x minus 2 right parenthesis plus r left parenthesis x squared minus 3 x plus 2 right parenthesis over denominator x cubed minus 2 x minus x plus 2 end fraction equals fraction numerator left parenthesis p plus q plus r right parenthesis x squared plus left parenthesis negative q minus 3 r right parenthesis x plus left parenthesis negative p minus 2 q plus 2 r right parenthesis over denominator x cubed minus 2 x squared minus x plus 2 end fraction$