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Pertanyaan

Tentukan nilai limit dari x → 3 lim ​ x 2 + 15 x + 36 x 2 − 5 x + 6 ​ !

Tentukan nilai limit dari  !

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Z. Apriani

Master Teacher

Mahasiswa/Alumni Institut Teknologi Bandung

Jawaban terverifikasi

Jawaban

.

 limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction equals 0.

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Pembahasan

Dengan mengganti nilai dengan , diperoleh: Jadi, .

Dengan mengganti nilai x dengan 3, diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction end cell equals cell limit as x rightwards arrow 3 of fraction numerator 3 squared minus 5 times 3 plus 6 over denominator 3 squared plus 15 times 3 plus 36 end fraction end cell row blank equals cell limit as x rightwards arrow 3 of 0 over 90 end cell row blank equals 0 end table

Jadi, limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction equals 0.

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