Tentukan nilai limit dari x→3lim​x2+15x+36x2−5x+6​ !

Pertanyaan

Tentukan nilai limit dari limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction !

Z. Apriani

Master Teacher

Mahasiswa/Alumni Institut Teknologi Bandung

Jawaban terverifikasi

Jawaban

 limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction equals 0.

Pembahasan

Dengan mengganti nilai x dengan 3, diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction end cell equals cell limit as x rightwards arrow 3 of fraction numerator 3 squared minus 5 times 3 plus 6 over denominator 3 squared plus 15 times 3 plus 36 end fraction end cell row blank equals cell limit as x rightwards arrow 3 of 0 over 90 end cell row blank equals 0 end table

Jadi, limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction equals 0.

111

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