Tentukan nilai limit dari x→3limx2+15x+36x2−5x+6 !

Pertanyaan

Tentukan nilai limit dari $limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction$ !

Z. Apriani

Master Teacher

Mahasiswa/Alumni Institut Teknologi Bandung

Jawaban terverifikasi

Jawaban

$limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction equals 0$ .

Pembahasan

Dengan mengganti nilai dengan , diperoleh:

$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction end cell equals cell limit as x rightwards arrow 3 of fraction numerator 3 squared minus 5 times 3 plus 6 over denominator 3 squared plus 15 times 3 plus 36 end fraction end cell row blank equals cell limit as x rightwards arrow 3 of 0 over 90 end cell row blank equals 0 end table$

Jadi, $limit as x rightwards arrow 3 of fraction numerator x squared minus 5 x plus 6 over denominator x squared plus 15 x plus 36 end fraction equals 0$ .

111

5.0 (3 rating)